Count from 1-100 using for
If a number is

Divisible by 7
Divisible by 11
Ends in 7

output "BUZZ!"

otherwise just output the number

You will need to use IF and % to do this
在1-100的数字里。如果一个数字能被7和11整除 或者结尾是7
就输出一个“BUZZ!”

另外 纸输出这个数字

#include<iostream>
using namespace std;
int main(void)
{
        for(int i=1;i<100;i++)
    {
        if(i%7==0)
        cout<<i<<' ';
        else if(i%11==0)
        cout<<i<<' ';
        else if (i%10==7)
        cout<<i<<' ';
    }

    cout<<endl;
}你看行不

什么意思？

#include "stdafx.h"
int main(int argc, char* argv[])
{
    int i;
    for (i=1;i<=100;i++){
        if(0==i%7|0==i%11|7==i%10){
            printf("BUZZ!");
        }
        printf("%d\n",i);
    }   
    return 0;
}

#include<iostream>
 using namespace std;
 int main(void)
 {
     for(int i=1;i<100;i++)
     {
         if(0==i%7||0==i%11||7==i%10)
            cout<<"BUZZ!"<<"    "<<i<<endl;
         else
            contiune;
     }
     return 0;
 }

#include <iostream>
using namespace std;
int main()
{
int i;
for(i=1;i<=100;i++)
{
if(i%7==0&&i%11==0||i%10==7)
cout<<"BUZZ!"<<endl;
else
cout<<i<<endl;
}
return  0;
}
应该是这样，错了请指正

[ 本帖最后由 风雨123 于 2013-2-24 14:40 编辑 ]

我觉得最后一个是对的

#include<iostream>
using namespace std;

int main()
{
    for(int num=1;num<=100;num++)
    {
        if(num%7!=0||num%11!=0||num%100%10!=7)
            cout<<num<<endl;
        else
            cout<<"BUZZ"<<endl;
    }
}

#include<iostream>
using namespace std;

int main()
{
    for(int num=1;num<=100;num++)
    {
        if(num%7!=0||num%11!=0||num%100%10!=7)
            cout<<num<<endl;
        else
            cout<<"BUZZ"<<endl;
    }
}