foreach (string image in images)
                    {
                        progressBar1.Value = progressBar1.Value + 1;
                        FileStream files = new FileStream(image, FileMode.Open, FileAccess.Read, FileShare.Read);
                        byte[] imgByte = new byte[files.Length];
                        files.Read(imgByte, 0, imgByte.Length);
                        StreamReader r = new StreamReader(files, Encoding.ASCII);
                        

                        if (imgByte[imgByte.Length - 1] != 0)
                        {
                            Bitmap Temp = new Bitmap(Image.FromStream(files));
                            files.Close();
                            narTemp = new Bitmap(imageList1.ImageSize.Width, imageList1.ImageSize.Height);
                            Graphics g = Graphics.FromImage(narTemp);
                           
                            Picsize = FitSize(Temp.Width, Temp.Height, narTemp.Width, narTemp.Height);
                            Point tempxy;
                            tempxy = PointXY(Picsize, narTemp.Width, narTemp.Height);
                            g.DrawImage(Temp, 0, 0, (int)(Temp.Width * Picsize.fitsize), (int)(Temp.Height * Picsize.fitsize));

                            imageList1.Images.AddStrip(narTemp);
                            if (progressBar1.Value == images.Count)
                            {
                                label3.Text = "加载完毕！";
                                label3.Refresh();
                            }
                            else
                            {
                                label3.Text = "已经加载" + progressBar1.Value.ToString() + "张";
                                label3.Refresh();
                            }
                            g.Dispose();
                            Temp.Dispose();
                            GC.Collect();

                        }
                    }

由于imagelist自动适配会使得图像走形 所以我将图像适配imagelist大小后重新绘制到imagelist中 但是问题是读取1MB以上的图像明显吃力 请问如何解决这一问题？