c是数组对数组怎么赋值？

想偷懒？一个个赋吧。

内存复制，够快吧

如果c是一维数组：
    如果c是int c[10];    1 c[10]={1,2,3,4,...};
                         2 循环赋值    for(i=0;i<10;i++)
                                        {
                                            c[i]=i+1;
                                        }
    如果c是char c[10];   1  c[10]="hello";    或者  char c[10]={'h','e','l','l','0'};
                         2  循环赋值   for(i=0,a='a';i<10;i++,a++)
                                        {
                                            c[i]=a;
                                        }
                         3  strcpy(c,"hello");
如果c是二维数组：
    如果c是int c[10][10];    1 c[10][10]={(1,2,3,4,5,...},{1,2,3,4,5,...},...};
                           2 循环赋值    for(i=0;i<10;i++)
                                         for(j=0;j<10;j++)
                                         {
                                             c[i][j]=j+1;
                                         }
    如果c是char c[10][10];   1  c[10][10]={"hello","world",...};    或者  char c[10][10]={{'h','e','l','l','0',...},{'w','o','r','l','d',...},...};
                           2  循环赋值   for(i=0;i<10;i++)
                                         for(j=0,a='a';j<10;j++,a++)
                                          {
                                              c[i][j]=a;
                                          }
                           3 strcpy(c[i],"hello");


[ 本帖最后由 小小战士 于 2012-12-5 21:06 编辑 ]

#include <stdio.h>

void StringCopy(char s1[],char s2[])
{
    int i=0;
    while((s1[i]-s2[i])!='\0')
    {
        i++;
    }
}

int main()
{
    char s1[100],s2[100];
    gets(s2);
    StringCopy(s1,s2);
    puts(s1);

    return 0;
}

这个应该可以吧

4l可以