数组问题
一组数组,(中间允许出现重复的数字不按顺序的输入1-49,不超过100个元素),然后在这组数组中找相同的数字,输出他们重复的次数,如果是没有出现在数组(1-49这个范围)的就被忽略,就是不显示在输出内容里!请各位帮帮忙,谢谢了。。。。。。
#include <stdio.h> int main (void) { int i=0,j=0,n=0,a[100],x,b=0,max=1; int num[49],l=0,k=1; printf("Enter the balls that are drawn from the machine: \n"); do { scanf("%d",&x); if (x>0&&x<49){ a[i]=x; i++; } }while (i<100 && x>0 && x<49); printf("\n\nThe values from 1st ball to the 6th ball are: \n"); for(j=0;j<6;j++) printf("%d ",a[j]); printf("\n\nThe 10th,20th and 30th balls: \n"); printf("10th ball: %d\n20th ball: %d\n30th ball:%d\n",a[9],a[19],a[29]); for(j=0;j<i;j++){ if (a[j] >40) b++; } printf("\nThe values are great than 40:%d\n",b); for(n=0;n<100;n++) { if(max<a[n]) max=a[n]; } printf("\nThe max vaule is : %d\n", max); for (l=0;l<100;l++)//频率 num[a[l]-1]++; for(k=1;k<=49;k++) printf("ball %d was drawn %d times",k,num[k]); return 0; }
#include <stdio.h> int main (void) { int i=0,j=0,n=0,a[100],x,b=0,max=1; int num[49],l=0,k=1; printf("Enter the balls that are drawn from the machine: \n"); do { scanf("%d",&x); if (x>0&&x<49){ a[i]=x; i++; } }while (i<100 && x>0 && x<49); printf("\n\nThe values from 1st ball to the 6th ball are: \n"); for(j=0;j<6;j++) printf("%d ",a[j]); printf("\n\nThe 10th,20th and 30th balls: \n"); printf("10th ball: %d\n20th ball: %d\n30th ball:%d\n",a[9],a[19],a[29]); for(j=0;j<i;j++){ if (a[j] >40) b++; } printf("\nThe values are great than 40:%d\n",b); for(n=0;n<100;n++) { if(max<a[n]) max=a[n]; } printf("\nThe max vaule is : %d\n", max); for (l=0;l<100;l++)//频率 num[a[l]-1]++; for(k=1;k<=49;k++) printf("ball %d was drawn %d times",k,num[k]); return 0; }