/*输入十个职工的姓名，职工号。
按职工号大小顺序输出，姓名也随着调整。
要求输入一职工号，折半查找，从主函
数输入要查找的职工号，输出该职工的姓名。*/

#include<stdio.h>
#include<string.h>
int main()
{
    int i,j,temp;int key;
    int p=0; char staffList[10];
    //char string[]
     char staffList[10]={{"刘翔","201003020076"},
                        {"姚明","20100302001"},
                        {"宋健","201003020077"},
                        {"宋丹丹","201003020054"},
                        {"马大文","201003020090"},
                        {"孙二林","201003020017"},
                        {"王三","201003020012"},
                        {"段五","201003020040"},
                        {"小六","201003020080"},
                        {"李四",201003020069"}};
    for(i=0;i<10;i++)
        scanf("staff=%lf\n",staffList[i]);
        for(j=0;j<10;j++)
            for(i=j;i<9-j;i++)
                if(staffList[i]>staffList[i+1]){
                    temp=staffList[i];
                staffList[i]=staffList[i+1];
                staffList[i+1]=temp;
                }
                for(i=0;i<10;i++)
                    printf("从小到大输出%f\n",staffList[i]);

                while(p==0){
                    printf("input a staff's number:\n");//折半查找？？？
                    scanf("%lf",&key);
                    if(key==staffList[i])
                    {
                        printf("%f ",staffList[i]);
                        p=1;
                    }
                            else{
                        
                        }
                    if(p==0)
                        printf("输入有误，重新出入！\n");
                }
                        return 0;        
}
//数组有误总改不对！求大神。。。

 char staffList[10]={{"刘翔","201003020076"},
                        {"姚明","20100302001"},
                        {"宋健","201003020077"},
                        {"宋丹丹","201003020054"},
                        {"马大文","201003020090"},
                        {"孙二林","201003020017"},
                        {"王三","201003020012"},
                        {"段五","201003020040"},
                        {"小六","201003020080"},
                        {"李四",201003020069"}};

我去。。。这只是一维数组。。。你这太让编译器为难了。。

本人新手，理解不透，这数组也太含蓄了啊，楼主，I服了you！！！！！！！！！！！！！！！！！！！！！！！

楼主，你太难为编译器了。
我是新手，说错勿怪：
#include<stdio.h>
#include<string.h>
int main()
{
    int i,j,temp;int key;
    int p=0; char staffList[10];
    //char string[]  /*这一行貌似没用*/
     char staffList[10]={{"刘翔","201003020076"},/*字符数组就是字符数组，整形数组就是整形数组，不能混用，
                        {"姚明","20100302001"},     就算能，我想也是高手用，新手还是老老实实分开定义两
                        {"宋健","201003020077"},    个数组吧，一个char，一个int*/
                        {"宋丹丹","201003020054"},    /*还有就算是当成二维数组理解也不对呀*/
                        {"马大文","201003020090"},
                        {"孙二林","201003020017"},
                        {"王三","201003020012"},
                        {"段五","201003020040"},
                        {"小六","201003020080"},
                        {"李四",201003020069"}};
    for(i=0;i<10;i++)
        scanf("staff=%lf\n",staffList[i]);/*%lf是浮点型的，和你的数组不符*/
        for(j=0;j<10;j++)
            for(i=j;i<9-j;i++)
                if(staffList[i]>staffList[i+1]){
                    temp=staffList[i];
                staffList[i]=staffList[i+1];
                staffList[i+1]=temp;
                }
                for(i=0;i<10;i++)
                    printf("从小到大输出%f\n",staffList[i]);/*这个%f也不对*/

                while(p==0){
                    printf("input a staff's number:\n");//折半查找？？？
                    scanf("%lf",&key);              /*这里没看出折半，只是让输入员工编号*/
                    if(key==staffList[i])         
                    {
                        printf("%f ",staffList[i]);
                        p=1;
                    }
                            else{
                        
                        }
                    if(p==0)
                        printf("输入有误，重新出入！\n");
                }
                        return 0;        
}
数组我也不太懂，改成这样不知道行不行
char staffList[10][]={"刘翔"，“徐达”，“蔡明”。。。。}；
int staff's_key[10][]={"123456","1234456"......};
字符数组和整型数组没法混用的。。。。

#include <stdio.h>
#include <stdlib.h>

int main ()

{
    char     staffList[10][2][100]= {{"刘翔","201003020076"},                //这是一个三维数组，10行，２列，高度100
                                    {"姚明","20100302001"},
                                    {"宋健","201003020077"},
                                    {"宋丹丹","201003020054"},
                                    {"马大文","201003020090"},
                                    {"孙二林","201003020017"},
                                    {"王三","201003020012"},
                                    {"段五","201003020040"},
                                    {"小六","201003020080"},
                                    {"李四","201003020069"}};

    int     i;
    int     j;

    for (i = 0;i < 10;i++)
        for (j = 0;j < 2;j++)
            printf ("%s\n", staffList[i][j]);

    return 0;
}

楼上高手，多维数组啊。。。。。没敢用过，

学习

5楼说的好像实现不了啊，定义的是字符数组char型的，那么每个元素就应该式2个字节，怎么去放整型啊，整型4个字节的，是不是会出错呀，没事过。
本人新手，说错勿怪，阿弥陀佛

三维数组 我也搞不清楚。。。谢谢哦。。。

你的问题  应该有一个结构  用类也可以  对于折半查找  你应该先和(a+b)/2进行比较  这才能显示出折半  对于排序  因为编号是字符串  应该用strcmp函数