#define Null 0

struct Books
    {   int num;
        struct Books *next;
        
    };
struct Books *creat()
    {   struct Books *p,*p1,*head;
        p=p1=malloc(sizeof(struct Books)) ;
        head=p;
        scanf("%d",p1->num);
        while(p1->num!=0)
            {
                p1=malloc(sizeof(struct Books)) ;
                p->next=p1;
                scanf("%d",p1->num);

            }
        p1->next=Null;
        return head;
        
        
    }
main()
{       struct Books *p2;
        p2=creat();
        while(p2!=Null)
            {   printf("%d",p2->num) ;
                p2=p2->next;
            }
         getch();


}



上面是自己做的简单链表建立并输出链表，虽然编译器能通过，但不能达到目的。自己挑了好久都不知道哪错了，有点烦，望大神们赐教。。。

scanf("%d",p1->num);

对么

#include <stdio.h>
 
struct Books
{   
    int num;
    struct Books *next;

};
struct Books *creat()
{   
    struct Books *p,*p1,*head;
    p = (int *)malloc(sizeof(struct Books)) ;
    head = p;
    scanf("%d",&(head->num));

    do
    {
        p1 = (int *)malloc(sizeof(struct Books)) ;
        p->next = p1;
        scanf("%d",&(p1->num));
        p = p->next;
    }while(p->num != 0);
    p1->next = NULL ;
    return head;
}

int  main()
{      
    struct Books *p2;

    p2=creat();
    while(NULL != p2)
    {  
        printf("%d\t",p2->num) ;
        p2=p2->next;
    }
}
 

你这链表机构上就有问题啊，我只是跟着你原来的意思去改的，最后还赋个0才退出，这样肯定不行，你自己再好好修改吧，祝学习进步

谢谢了