我想编一个程序，穷举n个人分m块钱的问题
之前试着编了一个10个人分100快钱的，用了10个for的嵌套，但是人数不定的话要怎么改呢？
之前看论坛上说用for实现不了，要用递归算法的非递归实现，自己模拟栈。然后用while来做循环。不是很明白。。。:'(
另，可能的话能不能把它改成并行计算的呢（算的实在太慢了）？求各位高手帮忙~~~~
a=zeros(1,101);
i=1;
for x1=0:10;
    for x2=x1:12;
        m2=x1+x2;
       for x3=x2:13;
           m3=m2+x3;
         for  x4=x3:15;
             m4=m3+x4;
           for   x5=x4:17;
               m5=m4+x5;
             for  x6=x5:20;
                 m6=m5+x6;
               for  x7=x6:25;
                   m7=m6+x7;
                  for  x8=x7:34;
                     m8=m7+x8;
                    for  x9=x8:50;
                        m9=m8+x9;
                        t=100-m9;
                       if t>=x9;
                            x10=t;
                            a(x1+1)=a(x1+1)+1;
                            a(x2+1)=a(x2+1)+1;
                            a(x3+1)=a(x3+1)+1;
                            a(x4+1)=a(x4+1)+1;
                            a(x5+1)=a(x5+1)+1;
                            a(x6+1)=a(x6+1)+1;
                            a(x7+1)=a(x7+1)+1;
                            a(x8+1)=a(x8+1)+1;
                            a(x9+1)=a(x9+1)+1;
                            a(x10+1)=a(x10+1)+1;
                         fid = fopen('d:\test.xls','a+t');
                            fprintf(fid,'%d\t  %d\t  %d\t  %d\t %d\t  %d\t  %d\t  %d\t %d\t %d\t %d\n',...
                           x1,x2,x3,x4,x5,x6,x7,x8,x9,x10,gn);                        
                            fclose(fid);
                         i=i+1;
                      end
                    end
                 end
               end
             end
           end
        end
      end
   end
end