Dim Path1() as string
Dim Path2() as string
Dim Path3() as string
Dim i ,j, k as intxxx
Const String1="甲"
Const String2="子"
j=0
for i=0 to 10*i-1 setp (1 or 2)
redim Pxxxx Path1(j)
Path1(j)=Chr(Asc(String1)+i)
'i要看是1字节或2字节
j=j+1
next i
j=0
for i=0 to 12*i-1 setp (1 or 2)
redim Pxxxx Path2(j)
Path2(j)=Chr(Asc(String2)+i)
'i要看是1字节或2字节
j=j+1
next i
k=0
for i=0 to UBound(Path1)
for j=0 to UBound(Path2)
redim Pxxxx Path3(k)
Path3(k)=Path1(i) & Path2(j)
k=k+1
next j
next i
猜大概是这感觉~
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本帖最后由 wube 于 2012-5-1 02:23 编辑 ]