#include<stdio.h>
void main(void)
{
  int i,j,n;
   printf("I WANT TO PUT THE CUBE IS:\n");
     scanf("%d",&n);
     for(i=0;i<n;i++)
        for(j=0;j<n;j++)
         {    if((i%2)==0)
                 printf("%d",4*i+j+1);
              if((i%2)!=0)
                 printf("%d",4*(i+1)+j);
              if(j=n-1) printf("\n");
         }
}
我的目的是打出回环数，但是为啥循环不了呢？？？

if(j=n-1)  为啥用=？

[ 本帖最后由 embed_xuel 于 2012-4-8 15:26 编辑 ]

什么 是回环数？  楼主最后一个if里面的=应该是==吧？

嗯，果真这里有错误，\(^o^)/~回环数就是1  2  3  4 这样的，自己取的名字，嘻嘻         
                                      8  7  6  5
                                      9 10 11 12            
                                      16 15 14 13
我的意图是#include<stdio.h>
void main(void)
{
  int i,j,n;
   printf("I WANT TO PUT THE CUBE IS:\n");
     scanf("%d",&n);
     for(i=0;i<n;i++)
        for(j=0;j<n;j++)
         {    if((i%2)==0)
                 printf("%8d",n*i+j+1);
              if((i%2)!=0)
                 printf("%8d",n*(i+1)-j);
              if(j==n-1) printf("\n");
         }
}