有个程序片段，其调用程序为：
      Elas3DT4 eq(theElement);
      eq.Deviator();
其中Elas3DT4是类，eq是对象，Deviator是类的成员，这个成语函数的定义为：
void Elas3DT4::Deviator(double coef)
{
   double c1=_G*_det*coef, c2=2*c1;
   for (size_t j=1; j<=4; j++) {
      double db11 = c2*_dSh(j).x;
      double db22 = c2*_dSh(j).y;
      double db33 = c2*_dSh(j).z;
      double db42 = c1*_dSh(j).z;
      double db43 = c1*_dSh(j).y;
      double db53 = c1*_dSh(j).x;
      for (size_t i=1; i<=4; i++) {
         eMat(3*i-2,3*j-2) += _dSh(i).x*db11 + _dSh(i).z*db42 + _dSh(i).y*db43;
         eMat(3*i-2,3*j-1) += _dSh(i).y*db53;
         eMat(3*i-2,3*j  ) += _dSh(i).z*db53;
         eMat(3*i-1,3*j-2) += _dSh(i).x*db43;
         eMat(3*i-1,3*j-1) += _dSh(i).y*db22 + _dSh(i).z*db42 + _dSh(i).x*db53;
         eMat(3*i-1,3*j  ) += _dSh(i).z*db43;
         eMat(3*i  ,3*j-2) += _dSh(i).x*db42;
         eMat(3*i  ,3*j-1) += _dSh(i).y*db42;
         eMat(3*i  ,3*j  ) += _dSh(i).z*db33 + _dSh(i).y*db43 + _dSh(i).x*db53;
      }
   }
}
    现在问题来了，由于这个成语函数是void类型，也就是没有返回值的，哪在调用语句eq.Deviator();中它把什么值传递出来呢？可能有几种传值的方式呢？请高手提点。

方法有很多，举个例子：比如我写一个函数，它接收两个整形参数，返回这两个数的“和”和这两个数的“积”：

#include <iostream>
using namespace std;

class Result {
public:
    Result(int s, int p) : sum(s), pdt(p) {}
    int getSum() const { return sum; }
    int getProduct() const { return product; }
private:
    int sum;
    int pdt;
};

const Result f(int a, int b) {
    return Result(a + b, a * b);
}

int main() {
    int a = 2, b = 3;
    Result r = f(a, b);
    cout << "The sum of a & b is: " << r.getSum() << endl;
    cout << "The product of a & b is: " << r.getProduct() << endl;
}

或者：

#include <iostream>
using namespace std;

void f(int a, int b, int& sum, int& pdt) {
    sum = a + b;
    pdt = a * b;
}

int main() {
    int a = 2, b = 3, sum, product;
    f(a, b, sum, product);
    cout << "The sum of a & b is: " << sum << endl;
    cout << "The product of a & b is: " << product << endl;
}

不明白楼主是啥意思啊