#include
void main()
{
char grade;
int salary = 1000;
double amt;
printf("从键盘输入员工级别grade:");
scanf("%f",&grade);
{if (grade=='A')
printf("%f\n",amt = salary + (salary * 0.45));
else
  { if(grade=='B')
   printf("%f\n",amt = salary + (salary * 0.40));
   else
   {if(grade=='C')
     printf("%f\n",amt = salary + (salary * 0.30));
       else
       {if(grade == 'D')
          printf ("%f\n",amt = salary + (salary * 0.25));
       }
        
   }

      
}
printf("无效的等级");
}
}
为什么程序执行结果总是显示“无效的等级”？？？

题目是：  定义：char grade; int salary = 1000; double amt; 从键盘输入员工级别rade。用if-else判断。若grade == 'A'则amt = salary + (salary * 0.45);并输出工资；若grade == 'B'则amt = salary + (salary * 0.40); 若grade == 'C'则amt = salary + (salary * 0.30);  若grade == 'D'  则amt = salary + (salary * 0.25);否则输出无效的等级。

scanf("%f",&grade);

#include<stdio.h>
void main()
{
char grade;
int salary = 1000;
double amt;
printf("从键盘输入员工级别grade:");
scanf("%c",&grade);//这里错咯字符要用%C来做
{if (grade=='A')
printf("%f\n",amt = salary + (salary * 0.45));
else
  { if(grade=='B')
   printf("%f\n",amt = salary + (salary * 0.40));
   else
   {if(grade=='C')
     printf("%f\n",amt = salary + (salary * 0.30));
       else
       {if(grade == 'D')
          printf ("%f\n",amt = salary + (salary * 0.25));
       }
        
   }

      
}
    if(grade!='A'&&grade!='B'&&grade!='C'&&grade!='D')//加个判断
    {
        printf("无效的等级");
    }
}

}
你可以用switch语句来做更方便

[ 本帖最后由 a646404908 于 2012-3-7 21:41 编辑 ]

谢谢啊。。。。我之前也有想过加判断语句的，可是肯能是括号那边出现了错误吧。。。。

#include<stdio.h>
void main()
{
    char grade;
    int salary = 1000;
    double amt;
    printf("从键盘输入员工级别grade:");
    scanf("%f",&grade);
{\\这层完全没用
    if (grade=='A')
        printf("%f\n",amt = salary + (salary * 0.45));
    else
    {
        if(grade=='B')
        printf("%f\n",amt = salary + (salary * 0.40));
        else
        {
            if(grade=='C')
                printf("%f\n",amt = salary + (salary * 0.30));
            else
                {
                    if(grade == 'D')
                    printf ("%f\n",amt = salary + (salary * 0.25));
                }
        } 

    }
    printf("无效的等级");\\这个并没有在任何一个条件分支内
}\\无用
}

}