程序代码：

/*+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

 *求方差，公式为[(x1-y)^2+(x2-y)+……]/n，其中xi为所求方差的数字，y为平均值，n为

 *所求方差的数字的个数

 *要求是输入整形数，返回整形数

 */
#include <stdio.h>
#include <math.h>

//int function(int *calculate[],int arrayLen);

int main(void)
{
    int calculate[3]={1,2,3};
    int arrayLen=3;
   

    printf("%d\n",function(calculate[3],3));
}

int function(int calculate[],int arrayLen)
{
    int i;
    float sum,average,square,square_average;
   

    for(i=0;i<arrayLen;i++)
        sum+=calculate[i];
    average=sum/arrayLen;
    for(i=0;i<arrayLen;i++)
        square_average+=((float)calculate[i]-average)
                         *((float)calculate[i]-average);
   

    return (int)square_average/arrayLen;
}