编写一个程序，要求用户输入下限整数和一个上限整数，然后，依次计算从下限到上限的每一个整数的平方的加和，最后显示结果。程序将不断提示用户输入下限整数和上限整数并显示出答案，直到用户输入的上限整数等于或小于下限整数为止。程序运行的结果示例应该如下所示：
    Enter lower and upper integer limits:  5 9
    The sums of the squares from 25 t0 81 is 255
    Enter next set of limits:3 25
    The sums of the squares from 9 t0 625 iS 5520
    Enter next set of limits:5 5
    Done
*******************************************************************************************************

#include "stdio.h"
#include "conio.h"
int main(void)
{
 int m,n,i;
 int sum=0 ;
 printf("Enter lower and upper integer limits:");
 scanf("%d%d",&m,&n);
 while (m<n)
 {
        for (i=m;i<=n;m++)
        sum+=i*i;
        printf("The sums of the squares fom %d to %d is %d",m*m,n*n,sum);
        sum=0;
        printf("Enter next set of limits:");
        scanf("%d%d",&m,&n);
 }
        printf("Done");
    getch();
    return 0;
}
**********************************************************************************

for (i=m;i<=n;m++)这里错了，是i＋＋
printf("The sums of the squares fom %d to %d is %d",m*m,n*n,sum);这里最后加个换行符
就行了

#include "stdio.h"
#include "conio.h"
int main(void)
{
int m,n,i;
int sum=0 ;
printf("Enter lower and upper integer limits:");
scanf("%d%d",&m,&n);
while (m<n)
{
        for (i=m;i<=n;i++)
            sum+=i*i; 
        printf("The sums of the squares fom %d to %d is %d\n",m*m,n*n,sum);
        sum=0;
        printf("Enter next set of limits:");
        scanf("%d%d",&m,&n);
}
        printf("Done");
    getch();
    return 0;
}

非常感谢！

看来以后还得更仔细才好。