这个程序有设么问题吗？？？
#include<stdio.h>
void main()
{
    int year,leap;
    scanf("year=%d",&year);
    if(year%4==0)
    {if(year%100==0)
        {if(year%400==0)
                leap=1;
            else
                leap=0;}
        
    else
            leap=1;}
            else
                leap=0;
            if(leap=1)
                printf("%d is a leap year\n",year);
            else(leap=0);
                printf("%d is not a leap year\n",year);
}
怎么结果都不对？？？

scanf("year=%d",&year);错
scanf("%d",&year);

.

不是啊  结果输出有问题，比方输入year=2000，输出地结果是2000 is a leap year和2000 is not a leap year

写得好混乱啊

在最后的if语句中，else后面不应该再有判断吧。。。去掉之后，运行结果正确。

建议输入格式为2楼的。

if(leap=1)  printf("%d is a leap year\n",year);
改为if(leap==1)  printf("%d is a leap year\n",year);

else(leap=0);//这里不能有分号
改为
else if(leap==0)

if(leap=1)
                printf("%d is a leap year\n",year);
            else(leap=0);
                printf("%d is not a leap year\n",year);
这两句有问题，if（）里面是个赋值语句，并不是判断语句应该是if（leap==1），else后面不用判断了，
if(leap==1)
        printf("%d is a leap year\n",year);
    else
        printf("%d is not a leap year\n",year);

#include "windows.h"
#include "stdio.h"
int main()
  {
     int year;
     printf("请输入所要查询年份：\n");
     scanf("%d",&year);
     if(year%400)
         if((year%100)&& !(year%4))   
            printf("%d 是闰年.\n",year);   
         else
            printf("%d 不是闰年.\n",year);
     else
         printf("%d 是闰年.\n",year);
      system("pause");
      return 0;   
   }              

支持2楼，能得到结果