public class mayer16 {
    public static void main(String[] args) {
        int[] num = new int[]{ 1, 3, 4, 5, 7, 8 };
        int[] nums = new int []{ 2, 3, 5, 6, 7, 9, 11 };
        for (int i = 0; i < num.length; i++) {
            for (int j = 0; j < nums.length; j++) {
                if (num[i] == nums[j]) {
                    System.out.println(num[i]);
                }
            }
        }
    }
}
这个是求出num和nums两个数组之间相同的数.怎么写能求出num有.nums没有的数.

public class XDeng {
    public static void main(String []args) {
        int[] s1 = new int[]{ 1, 3, 4, 5, 7, 8 };
        int[] s2 = new int []{ 2, 3, 5, 6, 7, 9, 11 };
        
        for(int i = 0 ; i < s1.length ; i++)
        {
            for(int j = 0 ; j < s2.length ; j++)
            {
                if(s1[i] == s2[j])
                {
                    s1[i] = s2[j]= 0;
                    break;                    
                }
            }               
        }
        System.out.println("整型数组s1中有，数组s2没有的元素有:");
        for(int i = 0 ; i < s1.length ; i++)
        {
            if(s1[i] != 0)
            {
                System.out.print(" " + s1[i]);   
            }   
        }
        System.out.println();
        System.out.println("整型数组s2中有，数组s1没有的元素有:");
        for(int j = 0 ; j < s2.length ; j++)
        {
            if(s2[j] != 0)
            {
                System.out.print(" " + s2[j]);   
            }   
        }   

    }   
}

public class mayer16 {
    public static void main(String[] args) {
        int[] num = new int[]{ 1, 3, 4, 5, 7, 8 };
        int[] nums = new int []{ 2, 3, 5, 6, 7, 9, 11 };
        for (int i = 0; i < num.length; i++) {
            for (int j = 0; j < nums.length; j++) {
                if (num[i] == nums[j]) {
                            break;        }
                System.out.print(num[i]);
            }
        }
    }
}

import java.util.*;

public class Test {
    public static void main(String[] args) {
        int[] num = { 1, 3, 4, 5, 7, 8 };
        int[] nums = { 2, 3, 5, 6, 7, 9, 11 };
        Map<Integer, Integer> mNum = new HashMap<Integer, Integer>();
        Map<Integer, Integer> mNums = new HashMap<Integer, Integer>();
        for (int i = 0; i < num.length; i++)
            mNum.put(num[i], num[i]);
        for (int i = 0; i < nums.length; i++)
            mNums.put(nums[i], nums[i]);
        for (int i = 0; i < num.length; i++)
            if (mNums.get(num[i]) == null)
                System.out.println(num[i]);
    }
} /* Output:
E:\Program\Java\bccn\2011-10-10>javac Test.java

E:\Program\Java\bccn\2011-10-10>java Test
1
4
8

E:\Program\Java\bccn\2011-10-10>
*/