#include<stdio.h>
void main()
{
    int a,b,c,i,p,z;
    float s,d,f,x;
printf("the exe can printf many \nfirst \n");
do{
    printf("1.bi da xiao\n2.nian fen\n3.pai xu\n4.tan qiou\n5. feng shu\n6.a+aa+aaa...=?\n");
    scanf("%d",&a);
    if(a==1)
    {
        do
    {
        printf("scanf there number the exe can bi da xiao\n");
        scanf("%d",&a);scanf("%d",&b);scanf("%d",&c);
        if(a>=b)
            p=a;
        else p=b;
        if(b>=c)
            z=b;
        else z=c;
        if(p>=z)
            printf("the max is %d\n",p);
        else printf("the max is %d\n",z);
         printf("if you want next scanf 1(y) or 2(n)\n");
        scanf("%d",&i);
    }
        while(i<=1);
    printf("ok next\n");
     }
    if(a==2)
    {
        do
    {
        printf("the exe can printf rain \nscanf a year \n");
        scanf("%d",&a);
        if(a%4==0)
            printf("%d is ",a);
        else printf("%d is not ",a);
        printf("rain\nif you want next scanf 1(y) or 2(n)\n");
        scanf("%d",&i);
    }
        while(i<=1);
    printf("ok next");
     }
    if(a==3)
    {
        do
    {
        printf("the exe can pai xu \n if you scanf number 1~3\nthe exe can scanf da to small\nps bu gou scanf 0\n");
        scanf("%d",&a);scanf("%d",&b);scanf("%d",&c);
        if(a<=b)
        {    i=b;
            b=a;
            a=i;
        }
        if(a<=c)
        {
            i=c;
            c=a;
            a=i;
        }
        if(b<=c)
        {
            i=c;
            c=b;
            b=i;
        }
        printf("%d ",a);printf("%d ",b);printf("%d ",c);
        printf("this is da xiao \nif you want next scanf 1(y) or 2(n)\n");
        scanf("%d",&i);
        
    }
        while(i<=1);
    printf(" next\n");
     }
    if(a==4)
        {
    do
    {
        a=0;d=0;s=0;f=0;
    printf("scanf a number tian qiou gao du \n1.ci shu 2.gao du\n");
        scanf("%d",&a);
         scanf("%f",&d);
    for(b=1;b<=a;)
          {
                s=d*2+s;
                 d=d/2;
                  b++;
        }
      f=s-100;
    printf("zhong gong ju li %f\ngao du %f\n",f,d);
     printf("the exe over \n next 1(y) or 2(n)\n");
    scanf("%d",&i);
    }
      while(i<=1);
        printf("over\n");
     }
    if(a==5)
        {
            do
            {
                printf("the exe can do feng shu jia fan \n scanf two number\n");
                printf("1. feng zhi \n2. feng mu \n3. ci shu \n");
                scanf("%f",&d);
                scanf("%f",&f);
                scanf("%d",&c);
    for(i=1;i<=c;)
    {
        s=s+f/d;
        x=f;
        f=d+x;
        d=x;
        i++;
    }
    printf("he %f",s);
    printf("the exe over \n next 1(y) or 2(n)\n");
    scanf("%d",&i);
    }
    while(i<=1);
        }
    if(a==6){
    do
    {
        printf("6.3 number jia fa \nscanf a=? the exe do a+aa+aaa....=?\n");
        printf("scanf a=?\n");
        scanf("%d",&a);
        printf("scanf ci shu \n");
        scanf("%d",&b);
        c=0;p=a;
        for(i=1;i<=b;)
        {
            
            c=c+p;
            p=10*p+a;
            i++;
        }
        printf("%d\n",c);
        printf("the exe over \n next 1(y) or 2(n)\n");
        scanf("%d",&i);
    }
    while(i<=1);
        }
    if(a==7){}
    printf("the exe over \n next 1(y) or 2(n)\n");
    scanf("%d",&i);
     }
    while(i<=1);
    printf("bey bey\n");
}
由于 没办法 让结尾 输入 Y N 结束 只能用 1 2 了 一周了 还得加油  老强的书看着好烦啊  后面真难

他的题  全部组装在一起了 方便 ~嘿嘿 但 废话1很多 希望各位大大多包容

而且英语 我真的很烂 却又不能 输出中文 MD 只能用 伪英语了 诶

对了 还有个很诡异的问题

#include<stdio.h>
void main()
{
int a,b,c;
    printf("scanf n");
    scanf("%d",&a);
    for(b=0;b<a;)
    {
       for(c=0;c<=b;)
        {  
            printf("**");
            c=c++;
        }
    printf("\n");
    b++;
    }
    scanf("%d",&c);
}
   



怎么才能输出     
*
***
*****
*******
*********
***********
啊
我改过很多次
有了
*
**
****
和
**
****
******
就是不能
*
***
***** 诶人笨了

这都说的啥？

第一个 比大小的
第二个 是否是闰年的
第三个 排大小的
第四个 百米弹球
第五个 那个很烦的分数加法
第六个 A+AA+AAA=?就
这些 都是老谭的题

由于方便我  改  和看结果 整成了 可以循环的 和换值的 看看 会不会溢出

是你发的 那个 学好 HELLO WORLD? 晚上我试试 看行不行 首先就没自信

#include<stdio.h>
void main()
{
    for(int i=1;i<=5;i+=2){
        for(int j=1;j<=i;j++)printf("*");
        printf("\n");
    }

}

试试呗，不成可以参考前面的帖子，有人写出来了，我也给过样板，看得懂的。