这段代码为什么达不到预期的效果？求指点
Option Explicit
Dim Filepath As String
Private Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As Long) As Long
Private Sub Command1_Click()
Filepath = "C:\Program Files\Microsoft Visual Studio\Common\Tools\Winapi\APILOAD.EXE"
ShellExecute 0, "open", Filepath, 0, 0, 4
End Sub

ShellExecute Me.hwnd, "open", Filepath, "", "", 4

谢谢，你是对的！
能说一下原因吗？

看看参数类型就知道了：(ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As Long)