//8.编写一个函数，要求输入年、月、日、时、分、秒，输出该时间的下一秒。
            //     如输入2010年12月31日23时59分59秒，则输出2011年1月1日0时0分0秒。


#include <stdio.h>

int main()
{
    int year=2010;
    int month=6;
    int day=3;
    int hour=7;
    int minute=55;
    int second=58;
    printf("%d年%d月%d日%d时%d分%d秒\n",year,month,day,hour,minute,second);
    while(!(second==58+1))
    {
        if (59==second)
        {
            second=0;
            if (59==minute)
            {
                minute=0;
                if (23==hour)
                {
                    hour=0;
                    if (30==day)
                    {
                        day=0;
                        if (11==month)
                        {
                            month=0;
                            year++;
                        }
                        else
                        {
                            month++;
                        }
                    }
                    else
                    {
                        day++;
                    }
                }
                else
                {
                    hour++;
                }
            }
            else
            {
                minute++;
            }
        }
        else
        {
            second++;
        }
    }
    printf("加1秒后的结果为:\n");
    printf("%d年%d月%d日%d时%d分%d秒\n",year,month,day,hour,minute,second);
    system("pause");
    return 0;
}

可以的哇  把那个while拿开就行了

简单的程序！尽然连指针都没有！！！