#include <stdio.h>

void convert(int n)//make integer  to became a string
{
    int i;
    char t;

    if((i=n/10)!=0)
         convert(i);
   // putchar();
   t=n%10+'0';
   printf("%c",t);
}

void main(int argc,char *argv[])
{
    int number;

    printf("please input a integer\n");
    scanf("%d",&number);//input the number which want to convert

    if(number<0)
        {
            putchar('-');
            number=-number;
        }

    convert(number);
}

在函数convert中 为什么输不出字符 这里远先是输出ASKII  即将一个整数转换为ASKII 输出 现在我是想把它转换为字符输出即使是一个小的数都不可以
求解为什么？

用while循环！

#include <stdio.h>

 
void convert(int n)//make integer  to became a string
 {
     int i;
     char t;

 
    if((i=n/10)!=0)    //
          convert(i);  //这两句没有任何意义
    // putchar();
    t=n%10+'0';  //任何整数到这里t都是一个0~9的字符！！！
    printf("%c",t);

 }

 
void main(int argc,char *argv[])

 {
     int number;

 
    printf("please input a integer\n");
     scanf("%d",&number);//input the number which want to convert
 
    if(number<0)
         {
             putchar('-');
             number=-number;
         }

 
    convert(number);

 }

#include <stdio.h>

void convert(int n)//make integer  to became a string
{
    int i;
    char t;

    if((i=n/10)!=0)
         convert(i);
   // putchar();
   t=n%10;
   printf("%c",t);
}

void main(int argc,char *argv[])
{
    int number;

    printf("please input a integer\n");
    scanf("%d",&number);//input the number which want to convert

    if(number<0)
        {
            putchar('-');
            number=-number;
        }

    convert(number);
}