从终端输入三角形的三条边，判断能否构成一个三角形，如果能够构成
三角形，判定其是否是直角三角形、等腰直角三角形、普通等腰三角形或等边三角形。

#include <stdio.h>
int judge(int a,int b,int c);
int main()
{
    int x,y,z,flag;
    scanf(" %d",&x);
    scanf(" %d",&y);
    scanf(" %d",&z);
    flag=judge(x,y,z);
    switch (flag)
    {
    case 1:
        printf("等边三角形");
        return 0;
    case 2:
        printf("等腰三角形");
        return 0;
    case 3:
        printf("普通三角形");
        return 0;
    case 4:
        printf("不能组成三角形");
        return 0;
    }
            return 0;
}
   
    int judge(int a,int b,int c)
    {
        int t;
        if(a==b&&b==c)return 1;//说明是等边三角形
        else
        {
            if(a<b)
            {
                t=a;
                a=b;
                b=t;
            }
            if(b<c)
                if(a<c)
                {
                    t=a;
                    a=c;
                    c=t;
                }
                else
                {
                    t=b;
                    b=c;
                    c=t;
                }
                if(a<b+c)
                    if(a==b||b==c)
                        return 2;//等腰三角形
                    else
                        return 3;//普通三角形
                    else return 4;//不是三角形
        }
    }

我也写一个

#include <stdio.h>
main()
{
    int a,b,c;
    scanf("%d%d%d",&a,&b,&c);
    if(a<b+c&&b<a+c&&c<a+b)
    {
      if(a==b&&b==c)
      printf("是等边三角形");
      else if(a==b||a==c||b==c)
      printf("是等腰三角形");
      else if(a*a==b*b+c*c||b*b==a*a+c*c||c*c==a*a+b*b)
      printf("是直角三角形");
      else
      printf("是普通三角形");
    }
    else
    printf("不能构成三角形");
}

受教了，呵呵

2楼写的结构化更强点

#include <stdio.h>
int judge(int a,int b,int c);
int main()
{
    int x,y,z,flag;
    scanf(" %d",&x);
    scanf(" %d",&y);
    scanf(" %d",&z);
    flag=judge(x,y,z);
    switch (flag)
    {
    case 1:
        printf("等边三角形");
        return 0;
    case 2:
        printf("等腰三角形");
        return 0;
    case 3:
        printf("普通三角形");
        return 0;
    case 4:
        printf("不能组成三角形");
        return 0;
    }
            return 0;
}
   
    int judge(int a,int b,int c)
   
    {
        hif(a<b+c&&b<a+c&&c<a+b)
    {
      if(a==b&&b==c)
      return 1;
      else if(a==b||a==c||b==c)
     return 2;
      else
      return 3;
    }
    else
      return 4;
}

二楼强悍