#include "stdio.h"
#include "stdlib.h"
struct node
{
    int Num;
    struct *next;
};
void main()
{
    struct node *head,*p,*q;   
    head=p=q=(struct node *)malloc(sizeof(struct node));
    scanf("%d",&p->Num);
    while(p->Num!=-1)
    {
        q=(struct node *)malloc(sizeof(struct node));
        scanf("%d",&q->Num);
        p->next=q;
        p=q;
    }
    p->next=NULL;
}

VC++6.0编译,有警告提示.类型不符合.应该怎么修改?
warning C4133: '=' : incompatible types - from 'struct node *' to 'struct $S1 *'

上述是一个简单的单向链表。求教.

不用了。。找到原因了。

#include "stdio.h"
#include "stdlib.h"
struct node
{
    int Num;
    node *next;
};
void main()
{
    node *head,*p,*q;   
    head=p=q=(struct node *)malloc(sizeof(struct node));
    scanf("%d",&p->Num);
    while(p->Num!=-1)
    {
        q=(struct node *)malloc(sizeof(struct node));
        scanf("%d",&q->Num);
        p->next=q;
        p=q;
    }
    p->next=NULL;
}

好了