main()
{
 struct student
 {
  int num;
  char name[10];
  int grade[3];
 };
 struct student a[]={{0,"andy",{89,23,43}},{1,"peter",{87,45,90}},{2,"t-bag",{99,90,98}}};
 struct student *p=a;
 void print(struct student *);
  print(p);
}
void print(struct student *s)  /* type mismatch */
{
 int n,m;
  for(n=0;n<3;n++,s++)
  {
   printf("number:%d\nname:%s\ngrade:",s->num,s->name);
   for(m=0;m<3;m++)
    printf("%4d",(*s).grade[m]);
   putchar('\n');
  }
}

你的代码很多地方写得不规范...函数名打错了都有....

是我看错

类型不匹配呀

#include <stdio.h>
#include <stdlib.h>

struct student
{
    int num;
    char name[10];
    int grade[3];
};

void print(struct student *s)  /* type mismatch */
{
int n,m;
  for(n=0;n<3;n++,s++)
  {
   printf("number:%d\nname:%s\ngrade:",s->num,s->name);
   for(m=0;m<3;m++)
       printf("%4d",(*s).grade[m]);
   putchar('\n');
  }
}

int main()
{

    struct student a[]={{0,"andy",{89,23,43}},{1,"peter",{87,45,90}},{2,"t-bag",{99,90,98}}};
    struct student *p=a;
    void print(struct student *);
    print(p);
    return 0;
}

调整下格式就好了，VC6

刚进来的，一点也不懂