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标题:用c如何编写 农历转换成公历
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小草鸟
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用c如何编写 农历转换成公历
请教各位高人如何用 c语言写 农历转换成公历 。
具体的算法是什么
搜索了各大小网站还是没有搜索到自己想要的结果,因此发帖,请高人指教一下小弟我
搜索更多相关主题的帖子: c语言 
2011-02-26 17:18
qq1023569223
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应该没有办法吧,没有规律的东西!

   唯实惟新 至诚致志
2011-02-26 17:38
Amy_huyier
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以前我也试图找过。据说,农历的计算是几个个天文上的复杂的方程算出来的
2011-03-01 14:02
刘定邦
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这。不好弄。。
2011-03-01 16:20
ansic
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农历太复杂。。。

善人者,不善人之师;不善人者,善人之资。不贵其师,不爱其资,虽智大迷。
2011-03-01 16:37
小小哥
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调用windows系统的吧……
2011-03-01 17:43
platolgq
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没有算过,楼主要是算出来了发出来看看

C种的自学者
2011-03-02 09:42
火男
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回复 楼主 小草鸟
楼主找到结果别忘了分享哦
2011-03-02 16:38
小草鸟
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经过我的寻找,我找到了一个较满意的答案,现在分享给论坛的兄弟姐妹们,不过这个代码有bug,也请高手过来帮我看看,完善一下代码://toSolar()农历转成公历    toLunar()公历转成农历


typedef struct _hjz{
    int year;
    int month;
    int day;
    int reserved;
} hjz;
unsigned int lunar200y[199] = {
    0x04AE53,0x0A5748,0x5526BD,0x0D2650,0x0D9544,0x46AAB9,0x056A4D,0x09AD42,0x24AEB6,0x04AE4A,/*1901-1910*/
    0x6A4DBE,0x0A4D52,0x0D2546,0x5D52BA,0x0B544E,0x0D6A43,0x296D37,0x095B4B,0x749BC1,0x049754,/*1911-1920*/
    0x0A4B48,0x5B25BC,0x06A550,0x06D445,0x4ADAB8,0x02B64D,0x095742,0x2497B7,0x04974A,0x664B3E,/*1921-1930*/
    0x0D4A51,0x0EA546,0x56D4BA,0x05AD4E,0x02B644,0x393738,0x092E4B,0x7C96BF,0x0C9553,0x0D4A48,/*1931-1940*/
    0x6DA53B,0x0B554F,0x056A45,0x4AADB9,0x025D4D,0x092D42,0x2C95B6,0x0A954A,0x7B4ABD,0x06CA51,/*1941-1950*/
    0x0B5546,0x555ABB,0x04DA4E,0x0A5B43,0x352BB8,0x052B4C,0x8A953F,0x0E9552,0x06AA48,0x6AD53C,/*1951-1960*/
    0x0AB54F,0x04B645,0x4A5739,0x0A574D,0x052642,0x3E9335,0x0D9549,0x75AABE,0x056A51,0x096D46,/*1961-1970*/
    0x54AEBB,0x04AD4F,0x0A4D43,0x4D26B7,0x0D254B,0x8D52BF,0x0B5452,0x0B6A47,0x696D3C,0x095B50,/*1971-1980*/
    0x049B45,0x4A4BB9,0x0A4B4D,0xAB25C2,0x06A554,0x06D449,0x6ADA3D,0x0AB651,0x093746,0x5497BB,/*1981-1990*/
    0x04974F,0x064B44,0x36A537,0x0EA54A,0x86B2BF,0x05AC53,0x0AB647,0x5936BC,0x092E50,0x0C9645,/*1991-2000*/
    0x4D4AB8,0x0D4A4C,0x0DA541,0x25AAB6,0x056A49,0x7AADBD,0x025D52,0x092D47,0x5C95BA,0x0A954E,/*2001-2010*/
    0x0B4A43,0x4B5537,0x0AD54A,0x955ABF,0x04BA53,0x0A5B48,0x652BBC,0x052B50,0x0A9345,0x474AB9,/*2011-2020*/
    0x06AA4C,0x0AD541,0x24DAB6,0x04B64A,0x69573D,0x0A4E51,0x0D2646,0x5E933A,0x0D534D,0x05AA43,/*2021-2030*/
    0x36B537,0x096D4B,0xB4AEBF,0x04AD53,0x0A4D48,0x6D25BC,0x0D254F,0x0D5244,0x5DAA38,0x0B5A4C,/*2031-2040*/
    0x056D41,0x24ADB6,0x049B4A,0x7A4BBE,0x0A4B51,0x0AA546,0x5B52BA,0x06D24E,0x0ADA42,0x355B37,/*2041-2050*/
    0x09374B,0x8497C1,0x049753,0x064B48,0x66A53C,0x0EA54F,0x06B244,0x4AB638,0x0AAE4C,0x092E42,/*2051-2060*/
    0x3C9735,0x0C9649,0x7D4ABD,0x0D4A51,0x0DA545,0x55AABA,0x056A4E,0x0A6D43,0x452EB7,0x052D4B,/*2061-2070*/
    0x8A95BF,0x0A9553,0x0B4A47,0x6B553B,0x0AD54F,0x055A45,0x4A5D38,0x0A5B4C,0x052B42,0x3A93B6,/*2071-2080*/
    0x069349,0x7729BD,0x06AA51,0x0AD546,0x54DABA,0x04B64E,0x0A5743,0x452738,0x0D264A,0x8E933E,/*2081-2090*/
    0x0D5252,0x0DAA47,0x66B53B,0x056D4F,0x04AE45,0x4A4EB9,0x0A4D4C,0x0D1541,0x2D92B5          /*2091-2099*/
};
int monthTotal[13] = {0,31,59,90,120,151,181,212,243,273,304,334,365};
hjz toSolar(hjz lunar){
    int year = lunar.year,
 month = lunar.month,
 day = lunar.day;
    int byNow, xMonth, i;
    hjz solar;
    byNow = (lunar200y[year-1901] & 0x001F) - 1;
    if( ((lunar200y[year-1901]&0x0060)>>5) == 2)
 byNow += 31;
    for(i = 1; i < month; i ++){
 if( ( lunar200y[year - 1901] & (0x80000 >> (i-1)) ) ==0){
     byNow += 29;
 }
 else
     byNow += 30;
    }
    byNow += day;
    xMonth = (lunar200y[year - 1901] & 0xf00000)>>20;
    if(xMonth != 0){
 if(month > xMonth
     ||(month==xMonth && lunar.reserved == 1)){
     if((lunar200y[year-1901] & (0x80000>>(month-1)))==0)
  byNow += 29;
     else
  byNow += 30;
 }
    }
    if(byNow > 366
     ||(year%4!=0 && byNow == 365)){
 year += 1;
 if(year%4==0)
     byNow -= 366;
 else
     byNow -= 365;
    }
    for(i=1; i <= 13; i ++){
 if(monthTotal[i] >= byNow){
     month = i;
     break;
 }
    }
    solar.day = byNow - monthTotal[month-1];
    solar.month = month;
    solar.year = year;
    return solar;
}
hjz toLunar(hjz solar){
    int year = solar.year,
 month = solar.month,
 day = solar.day;
    int bySpring,bySolar,daysPerMonth;
    int index,flag;
    hjz lunar;
    //bySpring 记录春节离当年元旦的天数。
    //bySolar 记录阳历日离当年元旦的天数。
    if( ((lunar200y[year-1901] & 0x0060) >> 5) == 1)
        bySpring = (lunar200y[year-1901] & 0x001F) - 1;
    else
        bySpring = (lunar200y[year-1901] & 0x001F) - 1 + 31;
    bySolar = monthTotal[month-1] + day - 1;
    if( (!(year % 4)) && (month > 2))
        bySolar++;
 
    //daysPerMonth记录大小月的天数 29 或30
    //index 记录从哪个月开始来计算。
    //flag 是用来对闰月的特殊处理。
    //判断阳历日在春节前还是春节后
    if (bySolar >= bySpring) {//阳历日在春节后(含春节那天)
        bySolar -= bySpring;
        month = 1;
        index = 1;
        flag = 0;
        if( ( lunar200y[year - 1901] & (0x80000 >> (index-1)) ) ==0)
            daysPerMonth = 29;
        else
            daysPerMonth = 30;
        while(bySolar >= daysPerMonth) {
            bySolar -= daysPerMonth;
            index++;
            if(month == ((lunar200y[year - 1901] & 0xF00000) >> 20) ) {
                flag = ~flag;
                if(flag == 0)
                    month++;
            }
            else
                month++;
            if( ( lunar200y[year - 1901] & (0x80000 >> (index-1)) ) ==0)
                daysPerMonth=29;
            else
                daysPerMonth=30;
        }
        day = bySolar + 1;
    }
    else {//阳历日在春节前
        bySpring -= bySolar;
        year--;
        month = 12;
        if ( ((lunar200y[year - 1901] & 0xF00000) >> 20) == 0)
            index = 12;
        else
            index = 13;
        flag = 0;
        if( ( lunar200y[year - 1901] & (0x80000 >> (index-1)) ) ==0)
            daysPerMonth = 29;
        else
            daysPerMonth = 30;
        while(bySpring > daysPerMonth) {
            bySpring -= daysPerMonth;
            index--;
            if(flag == 0)
                month--;
            if(month == ((lunar200y[year - 1901] & 0xF00000) >> 20))
                flag = ~flag;
            if( ( lunar200y[year - 1901] & (0x80000 >> (index-1)) ) ==0)
                daysPerMonth = 29;
            else
                daysPerMonth = 30;
         }
         day = daysPerMonth - bySpring + 1;
    }
    lunar.day = day;
    lunar.month = month;
    lunar.year = year;
    if(month == ((lunar200y[year - 1901] & 0xF00000) >> 20))
        lunar.reserved = 1;
    else
 lunar.reserved = 0;
    return lunar;
}


//以上是农历公历的函数。


不过这里有个bug 就是公历的1900-1-1 转成农历为1989-12-5(没有问题)
                但是农历的1989-12-5转成公历却是:1989-13-1(有问题)
因此请高人过来帮我们修改修改,让我们学习学习一下。
2011-03-03 16:54
小草鸟
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上面写错了是就是公历的1990-1-1 转成农历为1989-12-5(没有问题)
                但是农历的1989-12-5转成公历却是:1989-13-1(有问题)
2011-03-03 16:55
快速回复:用c如何编写 农历转换成公历
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