请问这个程序错在哪了？为什么输入2位时会不对 - 汇编论坛

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请问这个程序错在哪了？为什么输入2位时会不对

  DB 20 DUP(?)
   Y DB 20
     DB ?
  DB 20 DUP(?)
DATA ENDS
CODE SEGMENT
     ASSUME CS:CODE,DS:DATA,ES:DATA
START: MOV AX,DATA
       MOV DS,AX
       MOV ES,AX
       LEA DX,STR1
       MOV AH,9
       INT 21H
       LEA DX,X
       MOV AH,0AH
       INT 21H
       MOV BX,DX

       LEA DX,STR2
       MOV AH,9
       INT 21H
       LEA DX,Y
       MOV AH,0AH
       INT 21H
       MOV SI,DX
       MOV DX,0
  CMP BYTE PTR [BX+2],'-'
       JZ K23
       CMP BYTE PTR [BX+2],'0'
       JZ K0

K14:   CMP BYTE PTR [SI+2],'-'
       JZ K4
       CMP BYTE PTR [SI+2],'0'
       JZ K0
       MOV AH,2
MOV DL,'1'
       INT 21H
       JMP EXIT

K23:   CMP BYTE PTR [SI+2],'-'
       JZ K3
       CMP BYTE PTR [SI+2],'0'
       JZ K0

       MOV AH,2
       MOV DL,'2'
       JMP EXIT

K0:
       MOV AH,2
       MOV DL,'0'
       INT 21H
       JMP EXIT

K3:
       MOV AH,2
       MOV DL,'3'
       INT 21H
       JMP EXIT

K4:
       MOV AH,2
       MOV DL,'4'
       INT 21H

EXIT:  MOV AH,4CH
       INT 21H
CODE ENDS
     END START

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第 2 楼

得分:10

你能把你的代码先贴全么,呵呵

技术问题，请不要以短消息方式提问

第 3 楼

得分:10

程序代码：

data segment
    str1 db 'input a number: ',0dh,0ah,'$'
    str2 db 0dh,0ah,'input another number: ',0dh,0ah,'$'
    str3 db 'area','$'
    crlf db 0dh,0ah,'$'
    x db 20
        db ?
        DB 20 DUP(?)
   Y DB 20
     DB ?
  DB 20 DUP(?)
DATA ENDS

CODE SEGMENT
     ASSUME CS:CODE,DS:DATA,ES:DATA
START: MOV AX,DATA
       MOV DS,AX
       MOV ES,AX
      

       LEA DX,STR1
       MOV AH,9
       INT 21H
      

       LEA DX,X
       MOV AH,0AH
       INT 21H
      


       LEA DX,STR2
       MOV AH,9
       INT 21H
       LEA DX,Y
       MOV AH,0AH
       INT 21H
      

       mov dx,offset crlf
       mov ah,9
       int 21h
       MOV BX,offset x
       MOV SI,offset y
       ;MOV DX,0
        CMP BYTE PTR [BX+2],'-'
       JZ K23
       CMP BYTE PTR [BX+2],'0'
       JZ K0
    

K14:   CMP BYTE PTR [SI+2],'-'
       JZ K4
       CMP BYTE PTR [SI+2],'0'
       JZ K0
       MOV AH,2
        MOV DL,'1'
       INT 21H
       JMP EXIT

K23:   CMP BYTE PTR [SI+2],'-'
       JZ K3
       CMP BYTE PTR [SI+2],'0'
       JZ K0

 

       MOV AH,2
       MOV DL,'2'
       int 21h
       JMP EXIT

K0:  

       MOV AH,2
       MOV DL,'0'
       INT 21H
       JMP EXIT

K3:  

       MOV AH,2
       MOV DL,'3'
       INT 21H
       JMP EXIT

K4:  

       MOV AH,2
       MOV DL,'4'
       INT 21H
  

EXIT:

        mov dx,offset str3
        mov ah,9
        int 21h
        MOV AH,4CH
       INT 21H
CODE ENDS
     END START

这个问题好熟悉，在哪见过？

第 4 楼

得分:0

回复 3楼 xiaomarn

DATA SEGMENT
STR1 DB 'Please input X',0DH,0AH,'$'
STR2 DB 'Please input Y',0DH,0AH,'$'
F0   DB 'K is 0',0DH,0AH,'$'
F1   DB 'K is 1',0DH,0AH,'$'
F2   DB 'K is 2',0DH,0AH,'$'
F3   DB 'K is 3',0DH,0AH,'$'
F4   DB 'K is 4',0DH,0AH,'$'
   X DB 20
     DB ?
  DB 20 DUP(?)
   Y DB 20
     DB ?
  DB 20 DUP(?)
DATA ENDS
CODE SEGMENT
     ASSUME CS:CODE,DS:DATA,ES:DATA
START: MOV AX,DATA
       MOV DS,AX
       MOV ES,AX
       LEA DX,STR1
       MOV AH,9
       INT 21H
       LEA DX,X
       MOV AH,0AH
       INT 21H
       MOV BX,DX

       LEA DX,STR2
       MOV AH,9
       INT 21H
       LEA DX,Y
       MOV AH,0AH
       INT 21H
       MOV SI,DX

  CMP BYTE PTR [BX+2],'-'
       JZ K23
       CMP BYTE PTR [BX+2],'0'
       JZ K0

K14:   CMP BYTE PTR [SI+2],'-'
       JZ K4
       CMP BYTE PTR [SI+2],'0'
       JZ K0
       LEA DX,F1
       MOV AH,9
       INT 21H
       JMP EXIT

K23:   CMP BYTE PTR [SI+2],'-'
       JZ K3
       CMP BYTE PTR [SI+2],'0'
       JZ K0
       LEA DX,F2
       MOV AH,9
       INT 21H
       JMP EXIT

K0:    LEA DX,F0
       MOV AH,9
       INT 21H
       JMP EXIT

K3:    LEA DX,F3
       MOV AH,9
       INT 21H
       JMP EXIT

K4:    LEA DX,F4
       MOV AH,9
       INT 21H

EXIT:  MOV AH,4CH
       INT 21H
CODE ENDS
     END START

第 5 楼

得分:0

回复 3楼 xiaomarn

我把程序贴全了，就是检测XY判断在地基象限的，可是为什么么输入两位后输出值总是带了Y的值呢

第 6 楼

得分:0

回复 3楼 xiaomarn

DATA SEGMENT
STR1 DB 'Please input X',0DH,0AH,'$'
STR2 DB 'Please input Y',0DH,0AH,'$'
   X DB 20
     DB ?
  DB 20 DUP(?)
   Y DB 20
     DB ?
  DB 20 DUP(?)
DATA ENDS
CODE SEGMENT
     ASSUME CS:CODE,DS:DATA,ES:DATA
START: MOV AX,DATA
       MOV DS,AX
       MOV ES,AX
       LEA DX,STR1
       MOV AH,9
       INT 21H
       LEA DX,X
       MOV AH,0AH
       INT 21H
       MOV BX,DX

       LEA DX,STR2
       MOV AH,9
       INT 21H
       LEA DX,Y
       MOV AH,0AH
       INT 21H
       MOV SI,DX
       MOV DX,0
  CMP BYTE PTR [BX+2],'-'
       JZ K23
       CMP BYTE PTR [BX+2],'0'
       JZ K0

K14:   CMP BYTE PTR [SI+2],'-'
       JZ K4
       CMP BYTE PTR [SI+2],'0'
       JZ K0
       MOV AH,2
MOV DL,'1'
       INT 21H
       JMP EXIT

K23:   CMP BYTE PTR [SI+2],'-'
       JZ K3
       CMP BYTE PTR [SI+2],'0'
       JZ K0

       MOV AH,2
       MOV DL,'2'
       JMP EXIT

K0:
       MOV AH,2
       MOV DL,'0'
       INT 21H
       JMP EXIT

K3:
       MOV AH,2
       MOV DL,'3'
       INT 21H
       JMP EXIT

K4:
       MOV AH,2
       MOV DL,'4'
       INT 21H

EXIT:  MOV AH,4CH
       INT 21H
CODE ENDS
     END START

第 7 楼

得分:0

回复 4楼 flyfx1989

不好意思，第一个输出字符串没问题，第二个程序让直接输出字符就不对了，要怎么改呢

第 8 楼

得分:0

程序代码：

DATA SEGMENT
STR1 DB 'Please input X',0DH,0AH,'$'
STR2 DB 0DH,0AH,'Please input Y',0DH,0AH,'$'
F0   DB 0dh,0ah,'K is 0',0DH,0AH,'$'
F1   DB 0DH,0AH,'K is 1',0DH,0AH,'$'
F2   DB 0DH,0AH,'K is 2',0DH,0AH,'$'
F3   DB 0DH,0AH,'K is 3',0DH,0AH,'$'
F4   DB 0DH,0AH,'K is 4',0DH,0AH,'$'
   X DB 20
     DB ?
  DB 20 DUP(?)
   Y DB 20
     DB ?
  DB 20 DUP(?)
DATA ENDS

CODE SEGMENT
     ASSUME CS:CODE,DS:DATA,ES:DATA
START: MOV AX,DATA
       MOV DS,AX
       MOV ES,AX
      

       LEA DX,STR1
       MOV AH,9
       INT 21H
      

       LEA DX,X
       MOV AH,0AH
       INT 21H
      


       LEA DX,STR2
       MOV AH,9
       INT 21H
       LEA DX,Y
       MOV AH,0AH
       INT 21H
       MOV BX,offset x
       MOV SI,offset y

        CMP BYTE PTR [BX+2],'-'
       JZ K23
       CMP BYTE PTR [BX+2],'0'
       JZ K0
    

K14:   CMP BYTE PTR [SI+2],'-'
       JZ K4
       CMP BYTE PTR [SI+2],'0'
       JZ K0
      

       LEA DX,F1
       MOV AH,9
       INT 21H
       JMP EXIT

K23:   CMP BYTE PTR [SI+2],'-'
       JZ K3
       CMP BYTE PTR [SI+2],'0'
       JZ K0
      

       LEA DX,F2
       MOV AH,9
       INT 21H
       JMP EXIT

K0:    LEA DX,F0
       MOV AH,9
       INT 21H
       JMP EXIT

K3:    LEA DX,F3
       MOV AH,9
       INT 21H
       JMP EXIT

K4:    LEA DX,F4
       MOV AH,9
       INT 21H
  

EXIT:  MOV AH,4CH
       INT 21H
CODE ENDS
     END START

DATA SEGMENT
STR1 DB 0DH,0AH,'Please input X',0DH,0AH,'$'
STR2 DB 0DH,0AH,'Please input Y',0DH,0AH,'$'
str3 db 0DH,0AH,'$'
   X DB 20
     DB ?
  DB 20 DUP(?)
   Y DB 20
     DB ?
  DB 20 DUP(?)
DATA ENDS
CODE SEGMENT
     ASSUME CS:CODE,DS:DATA,ES:DATA
START: MOV AX,DATA
       MOV DS,AX
       MOV ES,AX
       LEA DX,STR1
       MOV AH,9
       INT 21H
       LEA DX,X
       MOV AH,0AH
       INT 21H
       MOV BX,DX

       LEA DX,STR2
       MOV AH,9
       INT 21H
       LEA DX,Y
       MOV AH,0AH
       INT 21H
       MOV SI,DX
       mov dx,offset str3
       mov ah,9
       int 21h
       MOV DX,0
        CMP BYTE PTR [BX+2],'-'
       JZ K23
       CMP BYTE PTR [BX+2],'0'
       JZ K0

K14:   CMP BYTE PTR [SI+2],'-'
       JZ K4
       CMP BYTE PTR [SI+2],'0'
       JZ K0

       MOV AH,2
        MOV DL,'1'
       INT 21H
       JMP EXIT

K23:   CMP BYTE PTR [SI+2],'-'
       JZ K3
       CMP BYTE PTR [SI+2],'0'
       JZ K0

       MOV AH,2
       MOV DL,'2'
       int 21h
       JMP EXIT

K0:
       MOV AH,2
       MOV DL,'0'
       INT 21H
       JMP EXIT

K3:
       MOV AH,2
       MOV DL,'3'
       INT 21H
       JMP EXIT

K4:
       MOV AH,2
       MOV DL,'4'
       INT 21H

EXIT:  MOV AH,4CH
       INT 21H
CODE ENDS
     END START

[ 本帖最后由 xiaomarn 于 2010-12-14 17:28 编辑 ]

第 9 楼

得分:0

回复 2楼 zaixuexi