#include<stdio.h>
main()
{
    int x=0,y=0;
    char i='y',j='\0';
    printf("hello world!\n");
    while(i=='y')
    {        
            
        printf("enter x and y\nx=");
        scanf("%d",&x);
        printf("y=");
        scanf("%d",&y);
        if (x==y)
            printf("x=y, no maximum.\n");
        else if (x>y)
            printf("x>y, x is the maximum.\n");
        else
            printf("x<y, y is the maximum.\n");   
        printf("enter 'y' or 'Y' to continue.\nand press others to quiet...\nyour choose is...");
   
        scanf("%c",&j);
        if (j=='y')
            i='\0';
        printf("\n*************************\n");
        
   
    }

}
为什么是死循环？？

scanf（"%c"，&j）;

怎么没有执行到？？

求解。

不知道你想表达什么 貌似猜值和比大小貌似没关系来着
我也是菜鸟 随便改的 你看下对么
#include<stdio.h>
main()
{
    int x=0,y=0;
    char i='y',j='\0',ch;
    printf("hello world!\n");
    while(i)
    {        
            
        printf("enter x and y\nx=");
        scanf("%d",&x);
        printf("y=");
        scanf("%d",&y);
        {if (x==y)
            printf("x=y, no maximum.\n");
        else if (x>y)
            printf("x>y, x is the maximum.\n");
        else
            printf("x<y, y is the maximum.\n");  }
        printf("j=\n");
        ch=getchar();
        ch=getchar();
        if (i==ch)
        { i='\0';
        printf("\n*************************\n");}
        else
            printf("too\n");

        
   
    }

}

解决了
是算法错了