#include "stdio.h"
#include "stdlib.h"
#define CNTL_Z '\032'
#define SLEN 50

int main(void)

{
     char file[SLEN];
     char ch;
     FILE *fp;
     long count,last;

     puts("enter the name of the file to be processed:");
     gets(file);
     if((fp = fopen (file,"rb"))==NULL)
     {
          printf("reverse can't open %s\n",file);
          exit(1);
     }

     fseek(fp,0L,SEEK_END);
     last=ftell(fp);
     for(count=1L,count<=last,count++)
     {
         fseek(fp,-count,SEEK_END);
         ch=getc(fp);
         if(ch!=CNTL_Z&&ch!='\r')
             putchar (ch);
         if(ch=='\r')
             putchar('\n');
         else
             putchar(ch);
     }
     putchar('\n');
     fclose(fp);
     return 0;


下面是错误信息，最近都是这个错误，求解中
Compiling...
frkd.c
C:\VC6\MyProjects\fseed\frkd.c(24) : error C2143: syntax error : missing ';' before ')'
C:\VC6\MyProjects\fseed\frkd.c(24) : error C2143: syntax error : missing ';' before ')'
执行 cl.exe 时出错.

留着回去看！

首先你在return 0；后面丢了个}
 其次 你的for有问题 是；；你的是,,( for(count=1L,count<=last,count++))

#include "stdio.h"
#include "stdlib.h"
#define CNTL_Z '\032'
#define SLEN 50

int main(void)

{
     char file[SLEN];
     char ch;
     FILE *fp;
     long count,last;

     puts("enter the name of the file to be processed:");
     gets(file);
     if((fp = fopen (file,"r+"))==NULL)
     {
          printf("reverse can't open %s\n",file);
          exit(1);
     }

     fseek(fp,0L,SEEK_END);
     last=ftell(fp);
     for(count=1L;count<=last;count++)
     {
         fseek(fp,-count,SEEK_END);
         ch=getc(fp);
         if(ch!=CNTL_Z&&ch!='\r')
             putchar (ch);
         if(ch=='\r')
             putchar('\n');
         else
             putchar(ch);
     }
     putchar('\n');
     fclose(fp);
     return 0;
}

没有质量的错误！

就是FOR循环的‘；’，嘿嘿，我一直都是用‘，’,现丑现丑

倒数十四行for语句格式错了应为for(语句1；语句；语句3)而不是，