#include <math.h>
#include <stdio.h>

main()
{
     float num1,num2,result;
     char answer,fuhao;
     int right;
     clrscr();/*清平*/
    printf("*********welcome to lin er ming's system*********");
    printf("\n");
     do
     {
         printf("please enter num1,fuhao,num2:");
         scanf("%f,%c,%f",&num1,&fuhao,&num2);/*可以修改输入，会更好*/
         printf("please enter your answer:");
         scanf("%f",&result);
         switch(fuhao)
         {
             case '+':if(result==(num1+num2)) right=1;
                         else
                           right=0;
                       break;
            case '-':if(result==(num1-num2)) right=1;
                       else
                           right=0;
                       break;
            case '*':if(result==(num1*num2)) right=1;
                       else
                           right=0;
                       break;
            case '/':if(num2==0) printf("\ninput wrong! ben ben,ha ha!!");
                       else
                       {
                           if(result==(num1/num2)) right=1;
                       else
                           right=0;
                        }
                           break;
         }
             if(right)
                 printf("\nyou are ringht!");
             else
                 printf("\nplease try again!");
                  printf("\ndo you want togo on?(please choose 'y'or'n')");
             scanf("%c",&answer);
            
            
     }while((answer=='y')||(answer=='Y'));/*这个时候输入y或者Y都不循环，怎么搞的*/
}
/* 各位哥哥姐姐，我吧answer给成char型了，不过在运行到scanf("%c",&answer);
它并不跳入输入界面我观测answer发现，scanf("%c",&answer);
不能让answer赋值，直接用answer='y'就行了，大家看看怎么才能让scanf("%c",&answer);
可以赋值给answer*//*我又发现程序运行后会自己赋值\n给answer*/

不带这样用激将法的。。。。

实在是没办法了，调一天了！！

问题确实很弱！！！
你这样改看看：
           scanf("%*c%c",&answer);
或者在原来的 scanf("%c",&answer);前面加个getchar();


[ 本帖最后由 jack10141 于 2010-10-13 12:54 编辑 ]

楼猪啊

晕，光知道说我，你怎么就不说说是什么问题呢，你要是不知道，你不和我一样啊

#include <math.h>
#include <stdio.h>
int  main()
{
    printf("z=%100d",300);
     float num1,num2,result;
     char answer,fuhao;
     int right;
    printf("*********welcome to lin er ming's system*********");
    printf("\n");
     do
     {
         printf("please enter num1,fuhao,num2:");
         scanf("%f%c%f",&num1,&fuhao,&num2);/*可以修改输入，会更好*/
         printf("please enter your answer:");
         scanf("%f",&result);
         switch(fuhao)
         {
             case '+':if(result==(num1+num2)) right=1;
                         else
                           right=0;
                       break;
            case '-':if(result==(num1-num2)) right=1;
                       else
                           right=0;
                       break;
            case '*':if(result==(num1*num2)) right=1;
                       else
                           right=0;
                       break;
            case '/':if(num2==0) printf("\ninput wrong! ben ben,ha ha!!");
                       else
                       {
                           if(result==(num1/num2)) right=1;
                       else
                           right=0;
                        }
                           break;
         }
             if(right)
                 printf("\nyou are ringht!");
             else
                 printf("\nplease try again!");
                 printf("\ndo you want togo on?(please choose 'y'or'n')");
                 getchar();
                 scanf("%c",&answer);
            
            
     }while((answer=='y')||(answer=='Y'));/*这个时候输入y或者Y都不循环，怎么搞的*/
}

楼上都说的是对的啊 ！还没理解啊！我帮你改下

版主，为什么像你scanf("%*c%c",&answer);这样加个%*c就可以了啊，加这个是什么意思啊，为什么我原来写的不行啊，错在哪里啊596615177

你的好像不行啊