int  main()
{
  int guess =1;
  printf("Pick an integer from 1 to 100.I will try to guess it\n");
  printf("Respond with a y if my guess is right and with\n");
  printf("an n if it is wrong.\n");
  printf("Uh...is your number %d ?\n",guess);
  while(getchar()!='y')
    {printf("Well,then,is it %d\n",++guess);
    while (getchar()!='\n')
    printf("xxxxxxx");
    continue;
    }
    printf("I knew I could do it!\n");


    return 0;

请帮我解释一下这个代码的循环部分，我的输入次序是n，回车，n其输出如图：
我是这样想的，输入n出现下一句，没有问题，但是我按回车后他是空了一行，显示下面那句，我认为他应该跳出循环了，接下来再按n就将xxxxxx打印出来，很迷惑。
请详细帮我解答一下这个问题，本人小菜。。。。多谢大侠指教。

int  main()
{
  int guess =1;
  printf("Pick an integer from 1 to 100.I will try to guess it\n");
  printf("Respond with a y if my guess is right and with\n");
  printf("an n if it is wrong.\n");
  printf("Uh...is your number %d ?\n",guess);
  while(getchar()!='y')  当输入的字符不等于字符'y‘ 就执行下面括号语句，也就是说当输入是字符‘y'时，就跳出循环
    {printf("Well,then,is it %d\n",++guess);   guess的 值 先加1后输出
    while (getchar()!='\n')当输入的 字符不是'\n'时就输出printf("xxxxxxx");
语句
    printf("xxxxxxx");
    continue;这个是跳出本次循环，注意是本次
    }
    printf("I knew I could do it!\n");


    return 0;

我用GCC编译。先 n 再 回车 再 n 没有你说的状况出现

Pick an integer from 1 to 100.I will try to guess it
Respond with a y if my guess is right and with
an n if it is wrong.
Uh...is your number 1 ?
n
Well,then,is it 2
n
Well,then,is it 3
n
Well,then,is it 4

我说了什么症状啊！？我是对你的代码进行解释。