项目一 小学生算术运算练习软件
功能：显示界面如下
1 加法运算
2 减法运算
3 乘法运算
4 除法运算
0 退出

要求：显示“是否继续做题”由Y/N选择，若选择Y，则继续做题
     数据由键盘输入

请问谁会做啊  会的请告诉我   好么 谢谢了

哥们，我们这里一般只改错，或者相对写些小代码，最好自己做一遍，我们再帮帮看看，提提意见。

#include<stdio.h>
#include <stdlib.h>
#include <time.h>
void main(void)
{
    int choice,a,b,c,s;
    char q='y';
    printf("1 加法运算\n");
    printf("2 减法运算\n");
    printf("3 乘法运算\n");
    printf("4 除法运算\n");
    printf("0 退出\n" );
    printf("请选择操作:");
    scanf("%d",&choice);
    while(q=='y')
    {

   
        switch (choice)
        {
        case 1:    srand(time(NULL));
                a=rand()%10;
                b=rand()%10;//随机产生个位数，可以自己修改数的范围
                c=a+b;
                printf("%d+%d= ",a,b);
                scanf("%d",&s);
                if(s==c)
                    printf("恭喜你，答对了！\n\n");
               
                else
                    printf("答错了，继续努力哦！\n\n");
                break;

        case 2:    srand(time(NULL));
                a=rand()%10;
                b=rand()%10;
                while(a<b)
                {
                    a=rand()%10;//防止a<b
                }

                c=a-b;
                printf("%d-%d= ",a,b);
                scanf("%d",&s);
                if(s==c)
                    printf("恭喜你，答对了！\n\n");
               
                else
                    printf("答错了，继续努力哦！\n\n");
                    break;
        case 3:    srand(time(NULL));
                a=rand()%10;
                b=rand()%10;
                c=a*b;
                printf("%d*%d= ",a,b);
                scanf("%d",&s);
                if(s==c)
                    printf("恭喜你，答对了！\n\n");
                        
                else
                    printf("答错了，继续努力哦！\n\n");
                break;
        case 4:    srand(time(NULL));
                a=rand()%10;
                b=rand()%10;
                while(a%b!=0||b==0)//防止除不尽以及除数为0的情况
                {
                    srand(time(NULL));
                    a=rand()%10;
                    b=rand()%10;
                }
                c=a/b;
                printf("%d/%d= ",a,b);
                scanf("%d",&s);
                if(s==c)
                    printf("恭喜你，答对了！\n\n");
                        
                else
                    printf("答错了，继续努力哦！\n\n");
                break;
        case 0:    printf("欢迎下次使用，再见！\n\n");
                exit(0);

        default: printf("输入有误！\n\n");

        }

        printf("是否愿意做题？按y继续！ \n");
        scanf("%s",&q);




    }
    printf("欢迎下次使用，再见！\n");

   
}

这是刚编的，有些不完善的，自己改下，希望能帮到你！！！