例：6 2 1
    4 5 2
    8 6 7
改为
    1 0 0
    0 0 0
    1 0 1
编写程序，将一个MXN的矩阵A存入一个二维数组，根据A生成一个新的矩阵B存入另外一个二维数组，生成的方法是：若A的某个元素是“局部最大值”，则B的相应元素设为1；否则设为0.所谓“局部最大值”是指该值比其上，下，左，右四个邻值都大

[ 本帖最后由 zhanfffmmm 于 2010-5-6 10:55 编辑 ]

  #include"stdio.h"
        main()
        {
            char b[3][3]={{6,2,1},{4,5,2},{8,6,7}};
            char a[3][3]={0};
            int i,j;

            for(i=0;i<5;i++)
              for(j=0;j<5;j++)
                {


                           if(b[i+1][j+1]>b[i+1][j]&&b[i+1][j+1]>b[i][j+1]&&b[i+1][j+1]>b[i+1][j+2]&&b[i+1][j+1]>b[i+2][j+1])
                            {
                             a[i][j]=1;
                             }
                           else
                           {
                            a[i][j]=0;
                           }
                       }


                 for(i=0;i<3;i++)
                  {
                     printf("\n");
                    for(j=0;j<3;j++)
                     {
                      printf("%d",a[i][j]);
                       }
                }

                      getch();
            }

#include"stdio.h"
  void   main()
  {
         char b[5][5]={{0,0,0,0,0},{0,6,2,1,0},{0,4,5,2,0},{0,8,6,7,0},{0,0,0,0,0}};//加围墙
            char a[3][3]={0};
            int i,j;

            for(i=1;i<4;i++)
              for(j=1;j<4;j++)
                {


                           if(b[i][j]>b[i+1][j]&&b[i][j]>b[i][j+1]&&b[i][j]>b[i-1][j+2]&&b[i][j]>b[i][j-1])
                            {
                             a[i-1][j-1]=1;
                             }
                           else
                           {
                            a[i-1][j-1]=0;
                           }
                       }


                 for(i=0;i<3;i++)
                  {
                     printf("\n");
                    for(j=0;j<3;j++)
                     {
                      printf("%d",a[i][j]);
                       }
                }

                      //getch();
            }

楼主我把2和3楼的程序在VC++6.0上运行了一下，发现2楼的好像不对。3楼的结果和思想都是正确的，可以推广到任意的数组上面。
2楼的结果：
001
010
000.

从键盘输入怎么定义啊