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标题:用顺序表实现多位大整数的:加、减、乘、除。~
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human84
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已结贴  问题点数:20 回复次数:7 
用顺序表实现多位大整数的:加、减、乘、除。~
如题;刚学数据结构很多地方还不知怎么写....谢谢大家。
搜索更多相关主题的帖子: 顺序 整数 
2010-04-04 11:36
lftp2020
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同求程序,帮顶!!
2010-04-04 11:47
Devil_W
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程序代码:
/*

 * Author: Devil Wang

 * Data: 01-21-2010

 * Notes: Template For BigInteger

 */
#include <deque>
#include <vector>
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;

class DividedByZeroException{};

class BigInteger
{
private:
     vector<char> digits; 
     bool sign;          //  true for positive, false for negitive
     void trim();        //  remove zeros in tail, but if the value is 0, keep only one:)
public:
     BigInteger(int);    // construct with a int integer
     BigInteger(string&) ;
     BigInteger();
     BigInteger (const BigInteger&);
     BigInteger operator=(const BigInteger& op2);

     BigInteger      abs() const;
     BigInteger    pow(int a);

     //binary operators
        
     friend BigInteger operator+=(BigInteger&,const BigInteger&);
     friend BigInteger operator-=(BigInteger&,const BigInteger&);
     friend BigInteger operator*=(BigInteger&,const BigInteger&);
     friend BigInteger operator/=(BigInteger&,const BigInteger&) throw(DividedByZeroException);
     friend BigInteger operator%=(BigInteger&,const BigInteger&) throw(DividedByZeroException);       

     friend BigInteger operator+(const BigInteger&,const BigInteger&);
     friend BigInteger operator-(const BigInteger&,const BigInteger&);
     friend BigInteger operator*(const BigInteger&,const BigInteger&);
     friend BigInteger operator/(const BigInteger&,const BigInteger&) throw(DividedByZeroException);
     friend BigInteger operator%(const BigInteger&,const BigInteger&) throw(DividedByZeroException);
   

     //uniary operators
     friend BigInteger operator-(const BigInteger&);   //negative

     friend BigInteger operator++(BigInteger&);        //++v
     friend BigInteger operator++(BigInteger&,int);    //v++
     friend BigInteger operator--(BigInteger&);        //--v
     friend BigInteger operator--(BigInteger&,int);    //v--

     friend bool operator>(const BigInteger&,const BigInteger&);
     friend bool operator<(const BigInteger&,const BigInteger&);
     friend bool operator==(const BigInteger&,const BigInteger&);
     friend bool operator!=(const BigInteger&,const BigInteger&);
     friend bool operator>=(const BigInteger&,const BigInteger&);
     friend bool operator<=(const BigInteger&,const BigInteger&);

     friend ostream& operator<<(ostream&,const BigInteger&);    //print the BigInteger
     friend istream& operator>>(istream&, BigInteger&);         // input the BigInteger

public:
     static const BigInteger ZERO;
     static const BigInteger ONE;
     static const BigInteger TEN;
};



const BigInteger BigInteger::ZERO=BigInteger(0);
const BigInteger BigInteger::ONE =BigInteger(1);
const BigInteger BigInteger::TEN =BigInteger(10);


BigInteger::BigInteger()
{
    sign=true; 
}


BigInteger::BigInteger(int val){// construct with a int integer
    if (val >= 0)
        sign = true;
    else{
        sign = false;
        val *= (-1);
    }
    do{
        digits.push_back( (char)(val%10) );
        val /= 10;
    } while ( val != 0 );
}


BigInteger::BigInteger(string& def){
    sign=true;
    for ( string::reverse_iterator iter = def.rbegin() ; iter < def.rend();  iter++){
        char ch = (*iter);
        if (iter == def.rend()-1){
            if ( ch == '+' )
                break;
            if(ch == '-' ){
                sign = false;
                break;
            }
        }
        digits.push_back( (char)((*iter) - '0' ) );
    }
    trim();
}

void BigInteger::trim(){
    vector<char>::reverse_iterator iter = digits.rbegin();
    while(!digits.empty() && (*iter) == 0){
        digits.pop_back();
        iter=digits.rbegin();
    }
    if( digits.size()==0 ){
        sign = true;
        digits.push_back(0);
    }
}


BigInteger::BigInteger(const BigInteger& op2){
    sign = op2.sign;
    digits=op2.digits;
}


BigInteger BigInteger::operator=(const BigInteger& op2){
    digits = op2.digits;
    sign = op2.sign;
    return (*this);
}


BigInteger BigInteger::abs() const {
    if(sign)  return *this;
    else      return -(*this);
}

BigInteger BigInteger::pow(int a) 
{
    BigInteger res(1);
    for(int i=0; i<a; i++)
        res*=(*this);
    return res;
}

//binary operators
BigInteger operator+=(BigInteger& op1,const BigInteger& op2){
    if( op1.sign == op2.sign ){     //只处理相同的符号的情况,异号的情况给-处理
        vector<char>::iterator iter1;
        vector<char>::const_iterator iter2;
        iter1 = op1.digits.begin();
        iter2 = op2.digits.begin();
        char to_add = 0;        //进位
        while ( iter1 != op1.digits.end() && iter2 != op2.digits.end()){
            (*iter1) = (*iter1) + (*iter2) + to_add;
            to_add = ((*iter1) > 9);    // 大于9进一位
            (*iter1) = (*iter1) % 10;
            iter1++; iter2++;
        }
        while ( iter1 != op1.digits.end() ){   // 
            (*iter1) = (*iter1) + to_add;
            to_add = ( (*iter1) > 9 );
            (*iter1) %= 10;
            iter1++;
        }
        while ( iter2 != op2.digits.end() ){
            char val = (*iter2) + to_add;
            to_add = (val > 9) ;
            val %= 10;
            op1.digits.push_back(val);
            iter2++;
        }
        if( to_add != 0 )
            op1.digits.push_back(to_add);
        return op1;
    }
    else{
        if (op1.sign)
            return op1 -= (-op2);
        else
            return op1= op2 - (-op1);
    }

}

BigInteger operator-=(BigInteger& op1,const BigInteger& op2){
    if( op1.sign == op2.sign ){
        if(op1.sign) { 
            if(op1 < op2)
                return  op1=-(op2 - op1);
        } 
        else {
            if(-op1 > -op2) 
                return op1=-((-op1)-(-op2));
            else            
                return op1= (-op2) - (-op1);
        }
        vector<char>::iterator iter1;
        vector<char>::const_iterator iter2;
        iter1 = op1.digits.begin();
        iter2 = op2.digits.begin();

        char to_substract = 0;  

        while ( iter1 != op1.digits.end() && iter2 != op2.digits.end()){
            (*iter1) = (*iter1) - (*iter2) - to_substract;
            to_substract = 0;
            if( (*iter1) < 0 ){
                to_substract=1;
                (*iter1) += 10;
            }
            iter1++;
            iter2++;
        }
        while ( iter1 != op1.digits.end() ){
            (*iter1) = (*iter1) - to_substract;
            to_substract = 0;
            if( (*iter1) < 0 ){
                to_substract=1;
                (*iter1) += 10;
            }
            else break;
            iter1++;
        }
        op1.trim();
        return op1;
    }
    else{
        if (op1 > BigInteger::ZERO)
            return op1 += (-op2);
        else
            return op1 = -(op2 + (-op1));
    }
}
BigInteger operator*=(BigInteger& op1,const BigInteger& op2){
    BigInteger result(0);
    if (op1 == BigInteger::ZERO || op2==BigInteger::ZERO)
        result = BigInteger::ZERO;
    else{
        vector<char>::const_iterator iter2 = op2.digits.begin();
        while( iter2 != op2.digits.end() ){
            if(*iter2 != 0){
                deque<char> temp(op1.digits.begin() , op1.digits.end());
                char to_add = 0;
                deque<char>::iterator iter1 = temp.begin();
                while( iter1 != temp.end() ){
                    (*iter1) *= (*iter2);
                    (*iter1) += to_add;
                    to_add = (*iter1) / 10;
                    (*iter1) %= 10;
                    iter1++;
                }
                if( to_add != 0)
                    temp.push_back( to_add );
                int num_of_zeros = iter2 - op2.digits.begin();
                while(  num_of_zeros--)
                    temp.push_front(0);
                BigInteger temp2;
                temp2.digits.insert( temp2.digits.end() , temp.begin() , temp.end() );
                temp2.trim();
                result = result + temp2;
            }
            iter2++;
        }
        result.sign = ( (op1.sign && op2.sign) || (!op1.sign && !op2.sign) );
    }
    op1 = result;
    return op1;
}

BigInteger operator/=(BigInteger& op1 , const BigInteger& op2 ) throw(DividedByZeroException) {
    if( op2 == BigInteger::ZERO )
        throw DividedByZeroException();
    BigInteger t1 = op1.abs(), t2 = op2.abs();
    if ( t1 < t2 ){
        op1 = BigInteger::ZERO;
        return op1;
    }
  
  
    deque<char> temp;
    vector<char>::reverse_iterator iter = t1.digits.rbegin();

    BigInteger temp2(0);
    while( iter != t1.digits.rend() ){
        temp2 = temp2 * BigInteger::TEN + BigInteger( (int)(*iter) );
        char s = 0;
        while( temp2 >= t2 ){
            temp2 = temp2 - t2;
            s = s + 1;
        }
        temp.push_front( s );
        iter++;
    }
    op1.digits.clear();
    op1.digits.insert( op1.digits.end() , temp.begin() , temp.end() );
    op1.trim();
    op1.sign = ( (op1.sign && op2.sign) || (!op1.sign && !op2.sign) );
    return op1;
}

BigInteger operator%=(BigInteger& op1,const BigInteger& op2) throw(DividedByZeroException) {
    return op1 -= ((op1 / op2)*op2);
}

BigInteger operator+(const BigInteger& op1,const BigInteger& op2){
    BigInteger temp(op1);
    temp += op2;
    return temp;
}
BigInteger operator-(const BigInteger& op1,const BigInteger& op2){
    BigInteger temp(op1);
    temp -= op2;
    return temp;
}

BigInteger operator*(const BigInteger& op1,const BigInteger& op2){
    BigInteger temp(op1);
    temp *= op2;
    return temp;

}

BigInteger operator/(const BigInteger& op1,const BigInteger& op2) throw(DividedByZeroException) {
    BigInteger temp(op1);
    temp /= op2;
    return temp;
}

BigInteger operator%(const BigInteger& op1,const BigInteger& op2) throw(DividedByZeroException) {
    BigInteger temp(op1);
    temp %= op2;
    return temp;
}


BigInteger operator-(const BigInteger& op){ 
    BigInteger temp = BigInteger(op);
    temp.sign = !temp.sign;
    return temp;
}

BigInteger operator++(BigInteger& op){   
    op += BigInteger::ONE;
    return op;
}

BigInteger operator++(BigInteger& op,int x){
    BigInteger temp(op);
    ++op;
    return temp;
}

BigInteger operator--(BigInteger& op){   
    op -=  BigInteger::ONE;
    return op;
}

BigInteger operator--(BigInteger& op,int x){
    BigInteger temp(op);
    --op;
    return temp;
}

bool operator<(const BigInteger& op1,const BigInteger& op2){
    if( op1.sign != op2.sign )
        return !op1.sign;
    else{
        if(op1.digits.size() != op2.digits.size())
            return (op1.sign && op1.digits.size()<op2.digits.size())
        || (!op1.sign && op1.digits.size()>op2.digits.size());
        vector<char>::const_reverse_iterator iter1,iter2;
        iter1 = op1.digits.rbegin();iter2 = op2.digits.rbegin();
        while( iter1 != op1.digits.rend() ){
            if(  op1.sign &&  *iter1 < *iter2 ) return true;
            if(  op1.sign &&  *iter1 > *iter2 ) return false;
            if( !op1.sign &&  *iter1 > *iter2 ) return true;
            if( !op1.sign &&  *iter1 < *iter2 ) return false;
            iter1++;
            iter2++;
        }
        return false;
    }
}
bool operator==(const BigInteger& op1,const BigInteger& op2){
    if( op1.sign != op2.sign  || op1.digits.size() != op2.digits.size() )
        return false;
    vector<char>::const_iterator iter1,iter2;
    iter1 = op1.digits.begin();
    iter2 = op2.digits.begin();
    while( iter1!= op1.digits.end() ){
        if( *iter1 != *iter2 )  return false;
        iter1++;
        iter2++;
    }
    return true;
}

bool operator!=(const BigInteger& op1,const BigInteger& op2){
    return !(op1==op2);
}

bool operator>=(const BigInteger& op1,const BigInteger& op2){
    return (op1>op2) || (op1==op2);
}

bool operator<=(const BigInteger& op1,const BigInteger& op2){
    return (op1<op2) || (op1==op2);
}

bool operator>(const BigInteger& op1,const BigInteger& op2){
    return !(op1<=op2);
}

ostream& operator<<(ostream& stream,const BigInteger& val){    //print the BigInteger
    if (!val.sign)
        stream << "-";
    for ( vector<char>::const_reverse_iterator iter = val.digits.rbegin(); iter != val.digits.rend() ; iter++)
        stream << (char)((*iter) + '0');
    return stream;
}

istream& operator>>(istream& stream, BigInteger& val){    //Input the BigInteger
    string str;
    stream >> str;
    val=BigInteger(str);
    return stream;
}

int main()
{
    string s1("3393232321873283792323280982092032738217389273");
    string s2("3201839283012930203232399999999999999999999999");
    cout<<BigInteger(s1)*BigInteger(s2);
    return 0;
}
2010-04-04 21:20
guangrongmen
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这摸多啊  我会慢慢读读看 谢谢了
路过
2010-04-04 22:37
human84
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谢谢...太...高深了...
2010-04-04 22:46
liuyafei
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可以用switch函数啊!
2010-04-06 19:00
zol7890
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汗 ,写那么多。你是工程师啊。厉害
2010-04-06 20:02
sd791002
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者明显是C++写的啊。。。。
2010-04-06 20:12
快速回复:用顺序表实现多位大整数的:加、减、乘、除。~
数据加载中...
 
   



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