#include <stdio.h>
#include <stdlib.h>
#include <time.h>

enum Status {CONTINUE,WON,LOST};

int rollDice(void);/*函数声明*/

int main(void)
{
  int  sum;
  int  mypoint;
  
  enum Status gameStatus;
  
  srand( time(NULL));
  
  sum = rollDice();
  
  switch(sum) {
  
  case 7:
  case 11:
     
     gameStatus = WON;
     break;
  case 2:
  case 3:
  case 12:
  
     gameStatus = LOST;
     break;
 
  default:
     gameStatus = CONTINUE;
     mypoint = sum;
     printf("point is %d\n",mypoint);
     break;
}
 
  while (gameStatus == CONTINUE) {
     sum = rollDice();
     
     if (sum ==mypoint) {
     gameStatus = WON;
     }
     
     else {
       if( sum==7){
       gameStatus = LOST;
     }
         }
             }

    if ( gameStatus==WON) {

       printf("Player wins\n");
    }
    else {
       printf("Player loses\n");}
    return 0;
}

 int rollDice(void)
{
   
  int die1;
  int die2;
  int workSum;
  
  die1 = 1+ (rand()%6);
  die2 = 1+ (rand()%6);
  workSum = die1+die2;
  printf(" Player rolled %d+%d =%d\n",die1,die2,workSum);
  
  return workSum;
}
 
现在这个程序是可以运行编译成功的,但是呢为什么做了两次enum定义呢？？分别是enum Status {CONTINUE,WON,LOST};和enum Status gameStatus; 为什么我直接enum gamesStatus，而不是用Status做一个过渡时 程序编译器就告诉我gameStatus未定义呢 这是为什么呢 谢谢

enum Status {CONTINUE,WON,LOST};是枚举的定义；
enum Status gameStatus;是声明一个枚举变量；
你若是不想用Status 可以这样
enum {
CONTINUE,WON,LOST
} gameStatus;

哦 谢谢您啊!