#include<iostream.h>
short fun2(short m)
{
    return m*m;
}

short fun1(short x,short y)
{
    return (fun2(short x)+fun2(short y));
}
void main()
{
    short a,b;
    cout<<"input two numbers"<<endl;
    cin>>a>>b;
    cout<<"a*a+b*b="<<fun1(a,b)<<endl;
}
这个错在哪里啊？？？
这个里面的fun1调用fun2里面，那个return语句错在哪里啊？？？？

解决了，谢谢．．汗

short fun1(short x,short y)                                        short fun1(short x,short y)
{                                                                                {
    return (fun2(short x)+fun2(short y)); 要改为               return (fun2(x)+fun2(y));
}                                                                                 }

因为你在short fun1(short x,short y)中，已经定义了x,y类型