include "stdio.h"
#include "conio.h"

main()
{ void average(float *p,int n);
  void search(float (*p)[4],int n)          //我问的是这里用float *p与用float (*p)[4]的区别？
  float score[3][4]={{65,67,70,60},{80,87,90,81},{90,99,100,98}};
  average(*score,12);
  search(score,2);                        
  getch();
}
void average(float *p,int n)
{float *p_end;
float sum=0,aver;
p_end=p+n-1;
for(;p<=p_end;p++)
sum=sum+(*p);
aver=sum/n;
printf("average=%5.2f\n",aver);
}
void search(float (*p)[4],int n)
{int i;                              
printf("the score of No.%d are:\n",n);
for(i=0;i<4;i++)
printf("%5.2f",*(*(p+n)+i));

include "stdio.h"
#include "conio.h"

main()
{ void average(float *p,int n);
  void search(float (*p)[4],int n)          //我问的是这里用float *p与用float (*p)[4]的区别？为什么调用同一个数组，但方式不一样？
  float score[3][4]={{65,67,70,60},{80,87,90,81},{90,99,100,98}};
  average(*score,12);
  search(score,2);                        
  getch();
}
void average(float *p,int n)
{float *p_end;
float sum=0,aver;
p_end=p+n-1;
for(;p<=p_end;p++)
sum=sum+(*p);
aver=sum/n;
printf("average=%5.2f\n",aver);
}
void search(float (*p)[4],int n)
{int i;                              
printf("the score of No.%d are:\n",n);
for(i=0;i<4;i++)
printf("%5.2f",*(*(p+n)+i));

#include <stdio.h>
#include <conio.h>

void average(float *p,int n);
void search(float (*p)[4],int n);          //我问的是这里用float *p与用float (*p)[4]的区别？
main()
{ 
    
    float score[3][4]={{65,67,70,60},{80,87,90,81},{90,99,100,98}};
    average((*score)+2,12);
    search(score+1,2);                         
    getch();
}
void average(float *p,int n)
{
    printf("%f\n", p[0]);
}
void search(float (*p)[4],int n)
{
    printf("%f\n", p[0][0]);
    printf("%f\n", p[1][0]);
}

这么写明白了么

明白了