代码如下
#include<stdio.h>
void display(char ch,int height,int width);
int main(void)
{
    char ch;
    int height,width;
    printf("Please enter a character and two integers\n");
    while((ch=getchar())!='\n')
    {
        char ch2;
        if(scanf("%d%d\n"&height,&width)!=2)
            break;
        display(ch,height,width);
        while((ch2=getchar())!='\n')
            continue;
        printf("Please enter another character and two integers\n");
        printf("Enter a new line to quit\n");
    }
    printf("Bye\n");
    return 0;
}

void display(char ch,int height,int width)
{
    int lines,rows;
    for(lines=1;lines<=height;lines++)
    {
        for(rows=1;rows<=width;rows++)
        printf("%5c\n",ch);
    }
}

红字为报错部分
 error C2296: “&”: 非法，左操作数包含“const char [6]”类型
什么意思？？

已找到错误，漏了一个逗号

TC下将 if(scanf("%d%d\n"&height,&width)!=2)改为  if(scanf("%d%d"，&height,&width)!=2)可以正常运行。但结果不知是否是想要的。