要求写一个求m,n最小公倍数的程序，m,m的最小公倍数为m*n除以他们的最大公约数。我写的程序如下，但在用visual2005执行时总会在启用时提示我没有定义m。。。我改如何改正？



#include <stdio.h>

int main()
{
   int m,n,a=1,r;
   
   
   printf("Enter a number:");
   scanf("%d",m);
   printf("Enter a number:");
   scanf("%d",n);
   for(m%a==0&&n%a==0;a<=m&&a<=n;a++)
   {
       if(m<=0||n<=0)
        {
          printf("The value are wrong!");
        }
   
       else r=(m*n/a);

   }
   printf("%d",r);
}

your code has one syntax error in the scanf function. you forget '&', before m and n.
in addition, you have to initialize m,n. this means you have to give a value to m, n when you created these two variables.

#include <stdio.h>

int main()
{
   int m = 0,n = 0,b=0;
      
   printf("Enter a number:");
   scanf(" %d",&m);
   printf("Enter a number:");
   scanf(" %d",&n);

   if (m > n)
       b = m;
   else
       b = n;

   while( (m%b != 0 || n%b !=0) && b > 1)
       b--;

   printf("%d",m*n/b);
}
you can refere to my code inorder to find 最小公倍数

这是我帮你改后的
#include <stdio.h>

int main()
{
   int m,n,a=1,r,t;
   
   
   printf("Enter a number:");
   scanf("%d",&m);//这里，你没有加&
   printf("Enter a number:");
   scanf("%d",&n);
   for(;a<=m&&a<=n;a++)
   {
       if(m<=0||n<=0)
        {
          printf("The value are wrong!");
        }
       if(m%a==0&&n%a==0)//还有这里，你不能一直用a，你要将他保存到另一个数上，不然你到最后a肯定是等于m或n的其中一个数
           t=a;
   }
        r=(m*n/t);

   
   printf("%d",r);
}

非常感谢~~~