用辗转相除法求出两个正整数m和n的最大公约数和最小公倍数

main()    {
        printf("input m and n:");
        scanf("%d,%d",&m,&n);    //赋值m，n
        if(n<m)        {    //把大的数放在在n中
            int temp = n;
            n = m;
            m = temp;
        }
        int p =n*m;   
        while(m!=0)    {    辗转相除法
            int r = n % m;
            n = m;
            m = r;
        }
        printf("最大公约数为：%d" + n);
        printf("最小公倍数为：%d" + p/n);
               
    }

楼上的有些小错误 ····在下改了一下··试试“注意输入两个数时，中间用逗号隔开！！！”
#include<stdio.h>
main()   
 {
    int m,n,r;
        printf("input m and n:");
        scanf("%d,%d",&m,&n);    //赋值m，n
        if(n<m)       //把大的数放在在n中
        {   
            int temp = n;
            n = m;
            m = temp;
        }
        int p =n*m;   
        while(r!=0)   
        {   
             r = n % m;
            n = m;
            m = r;
        }
        printf("最大公约数为：%d" , n);
        printf("最小公倍数为：%d" , p/n);
               
    }

大师真Hu````,不是输出么？？？害得我在输入那看了那么久···嘿嘿···