本人想把一个文件中的数字复制到另一个文件中,运行时一闪而过,但是文件也复制成功.为什么不显示结果.请专业的你修正下.

#include <stdio.h>
#define N 1000
mycopy();                             /* mycopy的原形说明*/
myout(int a[],int i);                 /*myout的原开说明*/  
main()
{int a=0,i=0;
FILE *Fp=NULL;

mycopy();                              /*调用cycopy*/
getch();
Fp=fopen("d:\\tan\\1.txt","r");
if(Fp==NULL)
{printf("can not open the file.\n");
exit(0);
}

while(feof(Fp)==0)
{fsanf(Fp,"%d",&a);
printf("%-3d",a);
i++;
if(i%10==0)
printf("\n");
}
sytem("pause");

fclose(Fp);
}
mycopy()
{int arry[N],i=0,b=0;
FILE *Fp=NULL;

Fp=fopen("d:\\tan\\0.txt","r");
if(Fp==NULL)
{printf("can not open the file.\n");
exit(0);
}

while(feof(Fp)==0)
{fscanf(Fp,"%d",&b);
arry[i]=b;
i++;
}

fclose(Fp);
myout(arry,i);                                 /*调用myout*/
}
myout(int a[],int i)
{int k=0;
FILE *Fp=NULL;

Fp=fopen("d:\\tan\\1.txt","w");
if(Fp==NULL)
{printf("can not open the file.\n");
exit(0);
}
for(k=0;k<i;k++)
fprintf(Fp,"%3d",a[k]);

fclose(Fp);

}

主函数的

mycopy();                              
getch(); /* 这句可以去掉，因为程序尾你已写个system("pause"); */
Fp=fopen("d:\\tan\\1.txt","r"); 
if(Fp==NULL) 
{printf("can not open the file.\n"); 
exit(0); 
} 
 

@
while(feof(Fp)==0) 
{fsanf(Fp,"%d",&a); /* 写错了，应是fscanf */
printf("%-3d",a); 
i++; 
if(i%10==0) 
printf("\n"); 
} 
sytem("pause"); /* 写漏s，应是system */

非常感谢。