大家好，大家帮我编一个程序，“今天是2008年12月31号，星期三，输入x天，可以输出这一天年月日和这一天是星期几”
  谢谢了，大家帮我啊

问一句，x是小于365呢还是任何可能的值？

你的意思是输入一年中的某一天，就比如2008年第300天，然后输出300天是周几是，还是输入一个很大的数然后输出年 月日星期啊？

谢谢你  x是任意值 不是小与365  这就得考虑闰年

谢谢啊  x是任意值

print(int year,int month)
{
    int i, j;
    printf("MON\tTUE\tWEB\tTHU\tFRI\tSAT\t\SUN\n");
    if(month==2)
    {
       if (year%4==0&&year%100!=0||year%100==0)
       {
 
            for(i=1;i<=29;i++)
            {
                int rest=(i-1+e[month-1]+year+(year/4)-year/100+year/400);
                  --rest;
                  rest%=7;
                     if(i==1)                   /* 确定1号打印的位置 */
                     {
                        if(rest==0)              /*判断1号是否为星期日*/
                        {
                            printf("\t\t\t\t\t\t");
                        }
                        else
                        {
 
                            for(j=1;j<(rest%7);j++)
                            {
                                printf("\t");
                            }
                        }
                     }
                printf("%d\t",i);
                if(rest%7==0)
                printf("\n");
            }
 
        }
        else
        {
 
 
 
            for(i=1;i<=28;i++)
            {
                int rest=(i-1+e[month-1]+year+(year/4)-year/100+year/400);
                rest%=7;
                if(i==1)                      /* 确定1号打印的位置 */
                {
                    if(rest==0)                 /*判断1号是否为星期日*/
                    {
                        printf("\t\t\t\t\t\t");
                    }
                    else
                    {
                        for(j=1;j<(rest%7);j++)
                        {
                            printf("\t");
                        }
                    }
                }
                printf("%d\t",i);
                if(rest%7==0)
                printf("\n");
            }
        }
 
    }
    else
    {
        if(month==1||month==3||month==5||month==7||month==8||month==10||month==12)
        {
            for(i=1;i<=31;i++)
            {
                int rest=(i-1+e[month-1]+year+(year/4)-year/100+year/400);
                rest%=7;
                if(i==1)                   /* 确定1号打印的位置 */
                {
                    if(rest==0)             /*判断1号是否为星期日*/
                    {
                        printf("\t\t\t\t\t\t");
                    }
                    else
                    {
                        for(j=1;j<(rest%7);j++)
                        {
                            printf("\t");
                        }
                    }
                 }
                 printf("%d\t",i);
                 if(rest%7==0)
                 printf("\n");
            }
         }
         else
         {
            for(i=1;i<=30;i++)
            {
 
                int rest=(i-1+e[month-1]+year+(year/4)-year/100+year/400);
                rest%=7;
                if(i==1)                   /* 确定1号打印的位置 */
                {
                    if(rest==0)              /*判断1号是否为星期日*/
                    {
                        printf("\t\t\t\t\t\t");
                    }
                    else
                    {
                        for(j=1;j<(rest%7);j++)
                        {
                            printf("\t");
                        }
                    }
                 }
                 printf("%d\t",i);
                 if(rest%7==0)
                 printf("\n");
            }
         }
    }
    printf("\n");
 
 
}

谢谢啊，辛苦了