#include "stdafx.h"

#include "stdio.h"
#include "string.h"

struct student
{
    long num;
    float score;
    struct student *next;
};

struct student *del(struct student *head1,struct student *head2)
{
    struct student *p1,*p2,*p3;
    for(p2=head2;p2!=NULL;p2=p2->next)
    {
        for(p1=head1;p1!=NULL;p3=p1,p1=p1->next)
        {
            if(p1->num==p2->num)               
            {
                if(p1==head1)
                    head1=p1->next;     
                else
                    p3->next=p1->next;  
        }
        }
    }
    return(head1);
}
struct student *del1(struct student *head1,struct student *head2)//这个函数为什么不能实现删除相同结点功能？代码该如何 编写？
{
    struct student *p1,*p2,*p3,*p4;
    for(p1=head1;p1!=NULL;p1=p1->next)
    {
        for(p2=head2;p2!=NULL;p4=p2,p2=p2->next)
        {
            if(p1->num==p2->num)
            {
                if(p2==head2)
                    head2=p2->next;
                else
                    p4->next=p4->next->next;
            }
        }
      
    }
     return (head2);
}

int main(int argc, char* argv[])
{
    struct student a,b,c,d,e,f,*head1,*head2,*p,*q,*w;
    a.num=99101;a.score=89;
    b.num=99102;b.score=90;
    c.num=99103;c.score=91;
    head1=&a;
    a.next=&b;
    b.next=&c;
    c.next=NULL;
    p=head1;
    printf("Linklist 1:\n");
    while(p!=NULL)
    {
        printf("%ld%5.1f\n",p->num,p->score);
        p=p->next;
    }
    printf("\n");
    d.num=99103;d.score=92;
    e.num=99104;e.score=93;
    f.num=99105;f.score=94;
    head2=&d;
    d.next=&e;
    e.next=&f;
    f.next=NULL;
    q=head2;
    printf("Linklist:\n");
    while(q!=NULL)
    {
        printf("%ld%5.1f\n",q->num,q->score);
        q=q->next;
    }
    printf("\n");
    head1=del(head1,head2);
    printf("delete Linklist 1:\n");
    for(p=head1;p!=NULL;p=p->next)
    {
       printf("%ld%5.1f\n",p->num,p->score);
      
    }
    head2=del1(head1,head2);
    printf("delete Linklist 2:\n");
    for(q=head2;q!=NULL;q=q->next)
    {
        printf("%ld%5.1f\n",q->num,q->score);
    }

    return 0;
}