#include<stdio.h>
void main()
{
 long int sum;
 int w,q,b,s,g,ws;
 printf("shu ru yi ge bu da yu wu wei de shu:");
 scanf("%ld\n",&sum);
 while(sum>9999)
  {
   printf("shu ru cuo wu:");
   scanf("%ld\n",&sum);
  }
  if(sum>9999) ws=5;
  else if(sum>999) ws=4;
  else if(sum>99) ws=3;
  else if(sum>9)  ws=2;
  else ws=1;
  w=(int)sum/10000;
  q=(int)(sum-w*10000)/1000;
  b=(int)(sum-w*10000-q*1000)/100;
  s=(int)(sum-w*10000-q*1000-b*100)/10;
  g=(int)(sum-w*10000-q*1000-b*100-s*10);
  switch(ws)
  {
   case 5: printf("sun xu shu chu:");
       printf("%d%d%d%d%d",w,q,b,s,g);
       printf("\ni xu shu chu:");
       printf("%d%d%d%d%d\n",g,s,b,q,w);
       break;
   case 4: printf("sun xu shu chu:");
       printf("%d%d%d%d\n",q,b,s,g);
       printf("%d%d%d%d\n",g,s,b,q);
       break;
   case 3: printf("sun xu shu chu:");
           printf("%d%d%d\n",b,s,g);
           printf("\ni xu shu chu:");
       printf("%d%d%d",g,s,b);
       break;
   case 2: printf("sun xu shu chu:");
           printf("%d%d\n",s,g);
           printf("\ni xu shu chu:");
       printf("%d%d",g,s);
       break;
   case 1: printf("%d",g);

  }
 }
输入的时候必须输入两次``输出的是第一次的结果```

scanf("%ld\n",&sum);
把\n去了，以后不要在scanf上加\n了

#include <stdio.h>
int main()
{
    int sum,a[5],i,count=0;
    scanf("%d",&sum);
    while(1){
        if(sum>9999){
            printf("shu ru cuo wu!\n");
            scanf("%d",&sum);
        }
        else{
            break;
        }
    }
    while(sum!=0){
        a[i++]=sum%10;
        sum/=10;
        count++;
    }
    for(i=0;i<count;i++){
        printf("%d",a[i]);
    }
    printf("\n");
    return 0;
}

谢谢

建议楼主学好英语，代码中使用汉语拼音是一大忌。

楼上的说的对！哈哈哈O(∩_∩)O哈哈~！！！！！！！！！1