老提示 Type mismatch in parameter 1 in call to 'print' in function maini 不知道错出在哪,知道的麻烦说下
#define N 10
struct student
{int num;
 char name[10];
 float score[3];
 float aver;
 };
main()
{int i,j;
 struct student stu[N];
 void print(struct student);<------ 必需要写完整形式void print(struct student stu[]);不然出错为什么啊
 for(i=0;i<N;i++)
  {printf("Input scores of student %d:\n",i+1);
   printf("NO.:");
   scanf("%d",&stu[i].num);
   printf("name:");
   scanf("%s",stu[i].name);
   for(j=0;j<3;j++)
    {printf("score %d:",j+1);
    scanf("%f",&stu[i].score[j]);
  }
 print(stu);
}
void print(struct sudent stu[])
{ printf("NO.  name   score1   score2 score3   aver\n");
  for(i=0;i<N;i++)
  {average=0;
   printf("%-3d%6s",stu[i].num,stu[i].name);
   for(j=0;j<3;j++)
   {printf("%8.2f",stu[i].score[j]);
   average+=stu[i].score[j];
   }
   stu[i].aver=average/3.0;
   printf("%8.2f\n",stu[i].aver);
  }
}

[[it] 本帖最后由 zgzhly 于 2008-12-12 17:21 编辑 [/it]]

#define N 10
struct student
{
    int num;
    char name[10];
    float score[3];
    float aver;
};
main()
{
    int i,j;
    struct student stu[N];
    void print(struct student);  /*这里，建议用全局结构体数组，然后把函数改为：void prin（）  */
    for(i=0;i<N;i++)
    {
        printf("Input scores of student %d:\n",i+1);
       printf("NO.:");
       scanf("%d",&stu[i].num);
       printf("name:");
       scanf("%s",stu[i].name);
       for(j=0;j<3;j++)
       {        
            printf("score %d:",j+1);
            scanf("%f",&stu[i].score[j]);
       }
       print(stu);
}  /* 这里 main 函数少了个大括号 */
void print(struct sudent stu[])  /* 这个函数里的i ,j , average从哪来的？没定义吧 */
{
    printf("NO.  name   score1   score2 score3   aver\n");
    for(i=0;i<N;i++)
    {
        average=0;
        printf("%-3d%6s",stu[i].num,stu[i].name);
        for(j=0;j<3;j++)
       {
          printf("%8.2f",stu[i].score[j]);
          average+=stu[i].score[j];
        }
        stu[i].aver=average/3.0;
        printf("%8.2f\n",stu[i].aver);
    }
}

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     先帮你看到这么多，并顺便帮你排下版。劝你一下，一定要格式清晰，不然自己出错了，都找不出哪的毛病。

谢谢了啊,问题找出来了!!