将S[2][2]复制给c[2][2];
请问那里出错了呢？谢谢！！

#include <stdio.h>
main()
{
    double s[2][2]={{0.1,0.2},{0.3,0.4}};
    double c[2][2];
    double copy2(double [],double [],int ,int );

    copy2(s,c,2,2);
}


double copy2(double s[],double c[],int i1,int i2)
{    
    int n1,n2;
    printf("copy2 is:\t");

    for(n1=0;n1<i1;n1++);
        {for(n2=0;n2<i2;n2++);
            {
            c[n1][n2]=s[n1][n2];
            printf("%.2f\t",c[n1])[n2);
            }
            printf("\n");
        }
    return(0);
}

double []
这个是一维数组,

作为参数的二维数组,必须至少指定第二维的长度,比如double[][2]

printf("%.2f\t",c[n1])[n2);
你这个括号怎么怎么奇怪

收到的鲜花

• ddc 于 2008-11-09 11:48 送鲜花  49朵  

谢谢你！
下面括号打错了，
double哪里的[]要改成[][2]呢
不好意思麻烦你再指教

我修改了，但打出的结果和原来的数组不一样

#include <stdio.h>
main()
{
    double s[2][2]={{1,2},{3,4}};
    double c[2][2];
    double copy2(double [][2],double [][2],int ,int );

    copy2(s,c,2,2);
}


double copy2(double s[][2],double c[][2],int i1,int i2)
{    
    int n1,n2;
    printf("Copy is:\t");

    for(n1=0;n1<i1;n1++);
        {for(n2=0;n2<i2;n2++);
            {
            c[n1][n2]=s[n1][n2];
            printf("%.2f\t",c[n1][n2]);
            }
            printf("\n");
        }
    return(0);
}

it is done. 3q~

#include <stdio.h>
double copy2(double s[][2],double c[][2],int i1,int i2)
{   
    int n1,n2;
    printf("copy2 is:\t");

    for(n1=0;n1<i1;n1++)
        {for(n2=0;n2<i2;n2++)
            {
            c[n1][n2]=s[n1][n2];
            printf("%.2f\t",c[n1][n2]);
            }
            printf("\n");
        }
    return(0);
}
main()
{
    double s[2][2]={{0.1,0.2},{0.3,0.4}};
    double c[2][2];
    copy2(s,c,2,2);
}

这次给DDC搞晕了，在FOR后面怎么加分号哦