那位高手小小给点提示就好了!

顶一下

我这里有个方法，是从网上找的。
        #region 获取光标位置代码
        private const int EM_GETSEL = 0xB0;
        private const int EM_LINEFROMCHAR = 0xC9;
        private const int EM_LINEINDEX = 0xBB;
        [DllImport("user32.dll", EntryPoint = "SendMessage")]
        public static extern int SendMessage(int hwnd,int wMsg,int wParam,ref int lParam);
        private Point GetCursorPos(int TextHwnd)
        {
            int i = 0, j = 0, k = 0;
            int lParam = 0, wParam = 0;
            i = SendMessage(TextHwnd, EM_GETSEL, wParam, ref lParam);
            j = i / 65536;
            int lineNo = SendMessage(TextHwnd, EM_LINEFROMCHAR, j, ref lParam) + 1;
            k = SendMessage(TextHwnd, EM_LINEINDEX, -1, ref lParam);
            int colNo = j - k + 1;
            Point ret = new Point(lineNo, colNo);
            return ret;
        }
        #endregion

这里返回一个point。然后下面：
            Point p = GetCursorPos(this.richTextBox1.Handle.ToInt32());
            this.statusStrip1.Items[2].Text = string.Format("第{0}行, 第{1}列", p.X, p.Y);

这个很容易,用textBox自带的属性个方法就好了

以下是代码,界面上有3个textBox,textBox1是输入框,2和3分别是行号和坐标

private void textBox1_MouseCaptureChanged(object sender, EventArgs e)
        {
            TextBox t = sender as TextBox;
            test(t);
        }

        private void textBox1_TextChanged(object sender, EventArgs e)
        {
            TextBox t = sender as TextBox;
            test(t);
        }

        private void test(TextBox box)
        {
            int a = box.SelectionStart;
            int b = box.GetLineFromCharIndex(a);
            int c = a - box.GetFirstCharIndexFromLine(b);
            this.textBox2.Text = (b + 1).ToString();
            this.textBox3.Text = c.ToString();
        }
就这么简单

LS,如果换成rachTextBox呢？求解

RichTextBox和TextBox一样,都有上述的方法和属性
不信你可以试试,将TextBox换成RichTextBox看看,效果是一样的!

原来如此，多谢了

学 了 一 招

不是很完美。
用上下左右键变动光标就没有反映了。

要举一反三啊,加个
private void textBox1_KeyUp(object sender, KeyEventArgs e)
        {
            RichTextBox t = sender as RichTextBox;
            test(t);
        }
不就完了吗