点解会运行不到～～～

题目；比较两个分数的大小

main() { int za,mb,zc,md; double p,q; printf("please input the number p of za/mb:\n"); scanf("%d%d",&za,&mb); p=za/mb; printf("please input the number q of zc/md:\n"); scanf("%d%d",&zc,&md); q=zc/md; if(p>q) printf("the bigger one is %d/%d",za,mb); else printf("the bigger one is %d/%d",zc,md); printf("\n"); }

我的问题是:比较两个分数的大小~!但是我运行了上面的程序时,比较不到大小!请哪位高手可以帮帮忙

main() { int za,mb,zc,md; double p,q; printf("please input the number p of za/mb:\n"); scanf("%d%d",&za,&mb); p=za/mb; printf("please input the number q of zc/md:\n"); scanf("%d%d",&zc,&md); q=zc/md; if(p>q) printf("the bigger one is %d/%d",za,mb); else printf("the bigger one is %d/%d",zc,md); printf("\n"); }

提示有错吗？ 要学好自己调程序？

有哪位高手可以帮帮忙哦????

搞到了~~!但是为什么要用float型来定义za,mb,zc,md的?不是很明白~~!

#include<stdio.h> void main() { float za,mb,zc,md; float p,q; printf("please input the number p of za/mb:\n"); scanf("%f%f",&za,&mb); p=za/mb; printf("please input the number q of zc/md:\n"); scanf("%f%f",&zc,&md); q=zc/md; if(p>q) printf("the bigger one is %f/%f",za,mb); else printf("the bigger one is %f/%f",zc,md); printf("\n"); }

两个int类型的数字用/进行运算,得到的仍然是int类型,比如

main()

{int a,b,c;

a=9;

b=2;

c=a/b;

prentf("c=%d",c);

}

运行的结果是c=4而不是4.5

明白不?

int也可以的，可以用通分的方法

比较za*md 和 mb*zc的大小

呵呵~~!谢谢各位高手~~!小弟明白了~~!而且有所改进了~~!请各位高手看看喇~~!

#include<stdio.h> void main() { float za,mb,zc,md; float p,q; printf("please input the number p of za/mb:\n"); scanf("%f%f",&za,&mb); p=za/mb; printf("please input the number q of zc/md:\n"); scanf("%f%f",&zc,&md); q=zc/md; if(p>q) printf("the bigger one is %d/%d",(int)za,(int)mb); else printf("the bigger one is %d/%d",(int)zc,(int)md); printf("\n"); }