程序代码：

/*

 * 一个数如果恰好等于它的因子之和，那么它就称为完数．

 * 例如，６的因子为１，２，３，而６＝１+２+３，因此

 * ６是完数．编程找出１０００内的所有完数，并且按照

 * 下面格式输出其因子：

 *　　　　　　　　６　its factors are 1,2,3

 */
#include <stdio.h>

#define SCOPE 1000
/* 1000 have 16 factors: 1,2,4,5,8,10,20,25,40,50,100,125,200,250,500,1000*/
#define N      16
#define TRUE  1
#define FALSE 0
int Factors[N];

int isFactor(int num,int vector)
{
    int result = FALSE;
    if( num % vector == 0)
    {
        result =TRUE;
    }
    return result;
}

main()
{
    int sum,target;
    int result,i,count;

    for(target = 2;target<=SCOPE;target++)
    {
        sum = 0;
        count=0;
        for(i=1;i<=target/2;i++)
        {
            if(isFactor(target,i))
            {
                sum += i;
                Factors[count++] = i;/*把找到的因子结果记录到表中*/
            }
        }
        if(sum == target)
        {
            printf("%d\t",target);
            printf("its factors are:");
            for(i=0;i<count;i++)
            {
                printf("%d,",Factors[i]);
            }
            printf("\n");
        }
     }
}