using System;
using System.Collections.Generic;
using System.Text;

namespace ConsoleApplication29
{  
    enum orientation : byte
       {
        north=1,
        south=2,
        east=3,
        west=4
    }
    struct route
    {
        public orientation direction;
        public double distance;
    }
    class Program
    {
     [STAThread]
        static void Main(string[] args)
        {
            route myroute;
            int mydirection = -1;
            double mydistance;
         Console.WriteLine("1)north\n2)south\n3)east\n4)west");
         do{
             Console.WriteLine("select a direction:");
             mydirection=Convert.ToInt32(Console.ReadLine());
         }
         while ((mydirection<1)||(mydirection>4));
         Console.WriteLine("input a distance:");
         mydistance = Convert.ToDouble(Console.ReadLine());
         myroute.direction=(orientation)mydirection;
         myroute.distance=mydistance;
         Console.WriteLine("myroute specifies a direction of {0} and a"+"distance of {1}",myroute.direction,myroute.distance);
     }
   
        }
    }


一直看不明白这个题的意思 包括显示结果的原理。尤其是红色不分一直想不明白这几个量究竟怎么回事 麻烦谁给指点下！

这是很基础的枚举和结构的知识
myroute.direction=(orientation)mydirection; //讲接收到的选择转换成枚举类型赋值给枚举对象的一个属性.如果你选择的是3，因为在枚举中3对应的是east。所以myroute.direction的值就是east
myroute.distance=mydistance;//讲输入的数据赋值给myroute对象的distance属性，如果你输入的是2.那么myroute.distance的值就是2

所以当你一次输入3，2，那么最后输出的内容将是
myroute specifies a direction of east and a distance of 2

谢谢  昨天看到今天都看的是这一点 就是想不明白 谢谢你指点！

//myroute.direction = (orientation)mydirection;
            //myroute.distance = mydistance;
            //Console.WriteLine("myroute specifies a direction of {0} and a" + "distance of {1}", myroute.direction, myroute.distance);
            //Console.ReadKey();
            Console.WriteLine("myroute specifies a direction of {0} and a" + "distance of {1}", mydirection, mydistance);
那里只是赋值给枚举对象的属性,可以不这样写  改成我那样写也可以的