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标题:倒酒问题!
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倒酒问题!
大杯中有12L酒,现只有8L和5L的酒杯,问如何才能倒出6L的酒!?
本人有一个利用递归解决问题的算法:
Option Explicit
Private Flags(12, 8, 5) As Byte
Private Direction(100, 1) As String * 1
Private Result(100, 2) As Byte
Private Bottle(2) As Byte
Private Lim(2) As Byte
Private Dir_Point As Byte, Result_Point As Byte
Private Action As Byte
Private A As Byte, B As Byte
Private Sub Form_Load()
  Me.Show
  Me.AutoRedraw = True
  InitializeAll
  Action = 0
  Direction(0, 0) = "\"
  Direction(0, 1) = "\"
  StartRunning
  Caption = Result_Point
End Sub
Private Sub Push_Result()
Dim I As Byte
   For I = 0 To 2
     Result(Result_Point, I) = Bottle(I)
   Next I
   Result_Point = Result_Point + 1
End Sub
Private Sub Push_Dir(From As Byte, Dest As Byte)
  Direction(Dir_Point, 0) = Chr(From + Asc("A"))
  Direction(Dir_Point, 1) = Chr(Dest + Asc("A"))
  Dir_Point = Dir_Point + 1
End Sub
Private Sub InitializeAll()
Lim(0) = 12: Lim(1) = 8: Lim(2) = 5
Bottle(0) = 12: Bottle(1) = 0: Bottle(2) = 0
 Dim I As Byte, J As Byte, K As Byte, L As Byte, M As Byte, N As Byte, O As Byte, R As Byte
 For I = 0 To 12
     For J = 0 To 8
       For K = 0 To 5
         Flags(I, J, K) = 0
       Next K
     Next J
 Next I
   
   For L = 1 To 100
     For M = 0 To 1
       Direction(L, M) = 0
   Next M, L
   
   For N = O To 100
     For R = 0 To 2
       Result(N, R) = 0
   Next R, N
   
   Dir_Point = 1
   Result_Point = 0
End Sub
Private Sub DoPrint()
Dim I As Byte
  Action = Action + 1
  Print "Action"; Action
  Print
  For I = 0 To Dir_Point - 1
    Print Direction(I, 0); "->"; Direction(I, 1), Result(I, 0); "-"; Result(I, 1); "-"; Result(I, 2)
  Next I
  Print
  Print
End Sub
Private Sub Countage(From As Byte, Dest As Byte)
  On Error GoTo Endness
  If Bottle(From) = 0 Then Exit Sub
  If Bottle(Dest) = Lim(Dest) Then Exit Sub
  A = Bottle(From): B = Bottle(Dest)
  Bottle(Dest) = Bottle(Dest) + Bottle(From)
  If Bottle(Dest) > Lim(Dest) Then
    Bottle(From) = Bottle(Dest) - Lim(Dest)
    Bottle(Dest) = Lim(Dest)
  Else
    Bottle(From) = 0
  End If
  If Flags(Bottle(0), Bottle(1), Bottle(2)) = 1 Then
    Bottle(From) = A: Bottle(Dest) = B
    Exit Sub
  Else
    Flags(Bottle(0), Bottle(1), Bottle(2)) = 1
  End If
  Push_Dir From, Dest
  Push_Result
  If Bottle(0) = 6 Or Bottle(1) = 6 Or Bottle(2) = 6 Then
    DoPrint
    Dir_Point = Dir_Point - 1
    Result_Point = Result_Point - 1
    Exit Sub
  End If
'_________________________________核心________________________________
  Countage 0, 1
  Countage 1, 0
  Countage 1, 2
  Countage 2, 1
  Countage 2, 0
  Countage 0, 2
'_______________________________________________________________________
  Exit Sub
Endness:
  End
End Sub
Private Sub StartRunning()
  Push_Result
  Flags(12, 0, 0) = 1
  Countage 0, 1
  InitializeAll
  Push_Result
  Flags(12, 0, 0) = 1
  Countage 0, 2
End Sub
不知有没有更简单的方法?

倒酒问题.rar (1.9 KB)
搜索更多相关主题的帖子: Byte Private Direction Result Point 
2007-12-08 20:43
jxyga111
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来 自:中華人民共和國
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先用5L倒入8L 再加一次五分之一 不就是6L了
2008-05-21 12:01
快速回复:倒酒问题!
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