<script language="javascript" type="text/javascript">
function judge()
{
if (document.form1.userpwd1.value=="")
{alert("请输入你的密码");
document.form1.userpwd1.focus()
document.form1.userpwd1.select()
return false;}
if (document.form1.userpwd2.value!=document.form1.userpwd1.value)
{alert("两次输入密码不一致,请重新输入");
document.form1.userpwd1.focus()
document.form1.userpwd1.select()
return false;}
if (document.form1.userpwd1.value.length<4||document.form1.userpwd1.value.length>8)
{alert("请输入4-8位的密码");
document.form1.userpwd1.focus()
document.form1.userpwd1.select()
return false;}

if (document.form1.nickname.value=="")
{alert("请输入你的昵称");
document.form1.nickname.focus()
document.form1.nickname.select()
return false;}


var regx=/^\d{5,9}$/;
if(!regx.test(document.form1.qq.value))
{alert("请输入你正确的QQ号");
document.form1.qq.focus()
document.form1.qq.select()
return false;}

}
</script>
<%

userid=session("userid")
userpwd1=session("userpwd1")
set myconn=Server.CreateObject("ADODB.Connection")
myconn.open "Provider = Microsoft.Jet.OLEDB.4.0;Data Source = "&server.Mappath("user.mdb")
set rs=server.CreateObject("ADODB.RecordSet")

rs.open "select * from [user] where userid='"&userid&"' ",myconn,1,1

nickname=rs("nickname")  
qq=rs("qq")


rs.close
end if
%>
<form id="form1" name="form1" method="post" oXsubmit="reXurn judge()" action="xgzl_cl.asp" > 　<--屏蔽了 ..只能用"oXsubmit="retXurn judge()" 代替" 　大家都明白！提交时激发judge()函数-->
新密码：<input name="userpwd1" type="text" class="heng" >
确认新密码：<input name="userpwd2" type="text" class="heng" >
昵称：<input name="nickname" type="text" class="heng"  value=<% =server.htmlencode (nickname)%>>
QQ:<input name="qq" type="text" class="heng" value= <% =server.htmlencode (qq)%> >
<input name="Submit" type="submit" class="loginbutton" value="提交" >
</form>
我也不知道那点错子　　看着都正确啊！　就是执行不了judge()函数进行不了判断！而在别的页面，同样的方法却能判断！郁闷　高手看看那里的问题，给指点一下，谢谢！　

<form id="form1" name="form1" method="post" oXsubmit="reXurn judge()" action="xgzl_cl.asp" >
改成
<form id="form1" name="form1" method="post" oXsubmit="return judge()" action="xgzl_cl.asp" >

找到问题了，谢谢！

哈  写代码时要细心才行````