我想利用forward方法实现一个页面的跳转，写了如下的代码，page是指需要跳转的页面，

public void forward(WebController servlet, HttpServletRequest request,
HttpServletResponse response, String page) throws ServletException {
try {
ServletContext ctx = servlet.getServletContext();
RequestDispatcher dispatcher = ctx.getRequestDispatcher(page);
if (dispatcher == null) {
throw new RuntimeException("NO dispatcher found for" + page);
} else
dispatcher.forward(request, response);//利用断点调式dispatcher一切正确，但就是不能跳转到我需要的页面，说页面不可用，那位大虾给讲讲是怎么回事！
} catch (Exception e) {
e.printStackTrace();
throw new ServletException("Failed to process request", e);
}
}

错误信息呢...

我记得:
dispatcher.forward();这个方法里是要跟具体一个jsp页面吧,不是你这样整的吧.你再试试!

错误的信息是：The requested resource (/goods/CustomerFindByPrimaryKeyResult.jsp) is not available.